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V125BC [204]
3 years ago
8

A costumer placed an order with a bakery for muffins.The Baker has completed 37.5% of the order after baking 81 muffins. How man

y muffins did the costumer order?
Mathematics
2 answers:
Elza [17]3 years ago
5 0
216 ? Maybe . I think you have to multiply 81 times .375 you move the decimal two places over . I believe that’s how you do the problem
Elena-2011 [213]3 years ago
3 0
37.5% = 0.375

81 / 0.375 = 216

The customer ordered 216 muffins.
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The perimeter of a rectangular meadow is 1004 m. What
nadezda [96]

Answer:

hope it works for u

Step-by-step explanation:

Given the length of the rectangle = l

the breadth  of the rectangle = b

perimeter of the rectangle = sum of length of all sides of the rectangle  

                                             = l+ b+ l+ b

                                             =2 l+2 b

                                             =2( l+ b)

∴ perimeter of the rectangle =2( l+ b)

as given perimeter = 1004 m

hence ,

2(l+ b)= 1004

(l+ b)=1004/2  = 502 m

<h2>l+ b=502 m</h2>

8 0
3 years ago
Answer part B please
oksano4ka [1.4K]
1:5

Steps:
1. Add all the numbers
2. Take Derek’s number of votes and turn step 1’s answer and Derek’s number of votes into a ration:
3. You will now have 36:180
4. Simplify by a number they both share (36).
5. Your new simplified answer would be 1:5.
4 0
3 years ago
Read 2 more answers
Which is equivalent to 3i ( 2i6)?
Hatshy [7]

Answer:

2 * (i^6) * (3 * i) =

- 6 i

Step-by-step explanation:

3 0
3 years ago
Factor the expression.
Veseljchak [2.6K]
15n-18. This is 3(5n-6) because 3 times 5n is 15n and 3 times 6 is 18.
8 0
3 years ago
Let v1,....., vk be vectors, and suppose that a point mass of m1,....., mk is located at the tip of each vector. The center of m
a_sh-v [17]

Answer: m1 = 4

m2 = 5

m3 = 2

Step-by-step explanation:

given (21/11, 6/11) = m1 (-1/3) + m2 (3, -2) + m3 (5, 2)

= (-m1 + 3m2 + 5m3) / 11 = 21/11

= (3m1 + (-2)m2 + 2m3) / 11 = 6/11

so that m1 + m2 +m3 = 11

-m1 + 3m2 + 5m3 = 21

3m1 - 2m2 + 2m3 = 6

from this, we get the augmented matrix as

\left[\begin{array}{cccc}-1&1&1&11\\-1&3&5&21\\3&-2&2&6\end{array}\right]

= \left[\begin{array{cccc}-1&1&1&11\\0&4&6&32\\0&-5&-1&-27\end{array}\right]  \left \{ {{R2=R2 + R1} \atop {R3=R3 -3R1 }]} \right.

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&-5&-1&-27\end{array}\right]

= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&0&13/2&13\end{array}\right]

(R3 = R3 + 5R2)

this gives m1 + m2 + m3 = 11

m2 + 3/2 m3 = 8

13/2 m3 = 8

13/2 m3 = 13

m3 = 2

m2 = 8 -3/2 (2) = 5

= m1 = 11- 5 - 2 = 4

this gives

m1 = 4

m2 = 5

m3 = 2

4 0
3 years ago
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