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yawa3891 [41]
4 years ago
6

what is the work done by a force equivalent to the weight of 100kg that moves an object in 7 minutes?​

Physics
1 answer:
Morgarella [4.7K]4 years ago
8 0
<h3>Answer:</h3>

7000 Joules

<h3>Explanation:</h3>

We are given;

  • The mass of an object = 100 kg

But, Force = mass × g (taking g as 10 N/kg)

  • Then, Force = 1000 N

Assuming we are given the distance moved by the object as 7 m

We can calculate the work done by the force

We need to know that;

Work done = Force × distance

Therefore;

Work done = 1000 N × 7 m

                   = 7000 Joules

Therefore, the work done by the force is 7000 Joules

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Define the terms resultant and equilibriant of
hjlf

Answer:

1) Resultant and Equilibrant explained below

2) Resultant = 24.18 N in a direction of 11.93° NE

3)Equilibrant = 24.18 N in a direction of 11.93° SW

Explanation:

1) Resultant force: If two or more forces are acting at a certain point, their resultant force would be defined as the force that when applied at that same point, it will have the exact same effect like the two independent forces acting together.

Equilibrant of 2 forces: This is defined as the force exactly equal and has an opposite direction to the resultant

2)a.) we are told that 10 N acts in the direction N 30 East and 15 N acts in the easterly direction, if both forces

act at a point. Thus, coordinates are;

(10cos30,10sin30) and (15,0)

Therefore, resultant coordinate is;

R→ = (10cos30, 10sin30) + (15, 0)

R→ = (15 + 10cos30, 0 + 10 sin 30)

This gives;

R→ = (23.66, 5)

Thus the resultant is;

R = √(23.66² + 5²)

R = √584.7956

R = 24.18 N

b) direction is gotten from;

tan θ = 5/23.66

θ = tan^(-1) 5/23.66

θ = 11.93° NE

c) Equilibrant is equal force but opposite direction. Thus, Equilibrant = 24.18 N in a direction of 11.93° SW

6 0
3 years ago
Difference between good and bad conductors of heat​
uranmaximum [27]

Good conductors are the materials which allow electricity to pass through them easily whereas, bad conductors are the materials which do not allow electricity to pass through them. Good conductors offer less resistance to the flow of current, whereas the bad conductors do not transmit current through them.

5 0
4 years ago
Read 2 more answers
A pair of fuzzy dice is hanging by a string from your rearview mirror. while you are accelerating from a stoplight to 28 m/s in
Lerok [7]
We can use the formula of motion in physics (2nd law od newton) in this problem:
x direction: Fsin ∅ = ma 
y direction: Fcos ∅ -mg = 0
∅ is equal to sin ∅ / cos ∅  or x/y
tan ∅ = ma / mg = a /g

Applying acceleration formula:
v = vo + at ; 28 = 0 + 6a ; a = 4.67 m/s^2
∅ = tan-1 (a/g) = tan-1 (4.67/9.81) = <span>25.4 degrees.</span>
4 0
3 years ago
True or false, As the frequency of an energy wave increases , so does its wavelength
hram777 [196]
False, the wavelength decreases as the frequency increases
6 0
3 years ago
Two point charges of +20.0 μC and -8.00 μC are separated by a distance of 20.0 cm. What is the intensity of electric field E mid
algol13

Answer:

The intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

Explanation:

Here we need first find the electric field due to the first charge at the midway point.

The electric field equation is given by:

|E_{1}|=k\frac{q_{1}}{d^{2}}

Where:

  • k is Coulomb's constant
  • q(1) is 20.00 μC or 20*10⁻⁶ C
  • d is the distance from q1 to the midpoint (d=10.0 cm)

So, we will have:

|E_{1}|=(9*10^{9})\frac{20*10^{-6}}{0.1^{2}}

|E_{1}|=1.8*10^{7}\: N/C

The direction of E1 is to the right of the midpoint.

Now, the second electric field is:

|E_{2}|=k\frac{q_{2}}{d^{2}}

|E_{2}|=(9*10^{9})\frac{8*10^{-6}}{0.1^{2}}

|E_{2}|=7.2*10^{6}\: N/C

The direction of E2 is to the right of the midpoint because the second charge is negative.

Finally, the intensity of the net electric field will:

E_{net}=E_{1}+E_{2}=2.52*10^{7}\: N/C

I hope it helps you!

5 0
3 years ago
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