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yawa3891 [41]
3 years ago
6

what is the work done by a force equivalent to the weight of 100kg that moves an object in 7 minutes?​

Physics
1 answer:
Morgarella [4.7K]3 years ago
8 0
<h3>Answer:</h3>

7000 Joules

<h3>Explanation:</h3>

We are given;

  • The mass of an object = 100 kg

But, Force = mass × g (taking g as 10 N/kg)

  • Then, Force = 1000 N

Assuming we are given the distance moved by the object as 7 m

We can calculate the work done by the force

We need to know that;

Work done = Force × distance

Therefore;

Work done = 1000 N × 7 m

                   = 7000 Joules

Therefore, the work done by the force is 7000 Joules

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Allisa [31]
False?


science can be a motivation out of curiosity AND societal needs.

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3 years ago
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An electron has a charge of 1.602 X 10-19.coulomb. When two electrons are separated by 1.2 X 10-9m, what force will they exert o
amid [387]

Answer:

The force they will exert on each other is 1.6*10⁻¹⁰ N

Explanation:

The electromagnetic force is the interaction that occurs between bodies that have an electric charge. When the charges are at rest, the interaction between them is called the electrostatic force. Depending on the sign of the interacting charges, the electrostatic force can be attractive or repulsive. The electrostatic interaction between charges of the same sign is repulsive, while the interaction between charges of the opposite sign is attractive.

Coulomb's law is used to calculate the electric force acting between two charges at rest. This force depends on the distance "r" between the electrons and the charge of both.

Coulomb's law is represented by:

F=k*\frac{q1*q2}{r^{2} }

where:

  • F = electric force of attraction or repulsion in Newtons (N). Like charges repel and opposite charges attract.
  • k = is the Coulomb constant or electrical constant of proportionality.
  • q = value of the electric charges measured in Coulomb (C).
  • r = distance that separates the charges and that is measured in meters (m).

In this case:

  • k= 9*10⁹ \frac{N*m^{2} }{C^{2} }
  • q1= 1.602*10⁻¹⁹ C
  • q2= 1.602*10⁻¹⁹ C
  • r= 1.2*10⁻⁹ m

Replacing:

F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{1.602*10^{-19} C*1.602*10^{-19} C}{(1.2*10^{-9} )^{2} }

and solving you get:

F=1.6*10⁻¹⁰ N

<u><em>The force they will exert on each other is 1.6*10⁻¹⁰ N</em></u>

3 0
3 years ago
A plane has a takeoff speed of 88.3 m/s and can accelerate at a rate of 3m/s to reach that speed. How long does the plane take t
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v = \frac{d}{t}

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a = \frac{v}{t}

We have acceleration and velocity so:

3 = \frac{v}{t}

88.3 = \frac{d}{t}

In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...

So...

3t = v

88.3 = 3t

Divide by three and

t = 29.4 s

3 0
3 years ago
A runner completes the 300 meter dash in 38 seconds what is the speed of the runner? Round your answer to the nearest tenth
grandymaker [24]
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If the electrons are attracted more by the nucleus because of an additional proton, what would happen to it?
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Answer:

orbital speed of the electrons in their orbit will increase

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4 0
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