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Diano4ka-milaya [45]
3 years ago
7

11. Meaningful digits in a measured quantity are known as??

Physics
1 answer:
-Dominant- [34]3 years ago
8 0
The significant figures also known as the significant digits or precision of a number written in positional notation are digits that carry meaningful contributions to its measurements
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A force F= (6.70 N)i + (5.60 N)j + (6.60 N)k act on a 9.80 kg mobile object that moves from an initial position of di = (9.10 m)
Mandarinka [93]

Answer:

W = 0.11J

P = 0.0186W

Explanation:

Please see attachment below.

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Who was the scientist that discovered Pluto wasnt a planet
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A particle travels in a circular orbit of radius 21 m. Its speed is changing at a rate of 23.1 m/s2 at an instant when its speed
Yuri [45]

The particle has an acceleration vector with one component directed toward the center of its orbit, and the other directing tangentially to its orbit. Call these components \vec a_c (c for center) and \vec a_t (t for tangent). Then its acceleration vector has magnitude

|\vec a|=\sqrt{\|\vec a_c\|^2+\|\vec a_t\|^2}

We have

\|\vec a_c\|=\dfrac{\|\vec v\|^2}r

where \|\vec v\| is the particle's speed and r is the radius of orbit, so

\|\vec a_c\|=\dfrac{\left(37.2\frac{\rm m}{\rm s}\right)^2}{21\,\rm m}=65.9\dfrac{\rm m}{\mathrm s^2}

We're given that the particle's speed changes at a rate of 23.1 m/s^2. Its velocity vector points in the same direction as \vec a_t, i.e. perpendicular to \vec a_c, so

\|\vec a_t\|=23.1\dfrac{\rm m}{\mathrm s^2}

Then the magnitude of the particle's acceleration is

\|\vec a\|=\sqrt{\left(65.9\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(23.1\dfrac{\rm m}{\mathrm s^2}\right)^2}=\boxed{69.8\dfrac{\rm m}{\mathrm s^2}}

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3 years ago
When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room. Which sentence explains t
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When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room because gases do not have a definite volume.

Hope this helps!
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3 years ago
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