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zhuklara [117]
3 years ago
9

HELP ME

Physics
1 answer:
Mazyrski [523]3 years ago
3 0

Answer:

I THINK IT'S <em>D.</em><em>.</em><em>.</em><em>.</em>

<em>HOPE </em><em>SO</em>

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Why is Venus sometimes called Earth’s twin?
monitta

Answer:

B.

Venus is the same size and density.

Explanation:

It is becuase venus has the same size and density as earth

8 0
3 years ago
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Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne
slega [8]

Answer:

\epsilon = 2.96 \times 10^{-11} \ V

Explanation:

given,

magnetic field strength =  1.40 ✕ 10⁻³ T

frequency of oscillation = 60 Hz

diameter of RBC = 7.5 μm

EMF = ?

\epsilon = NBA\omega

\epsilon = NB(\pi\ r^2)\ (2\pi f)

\epsilon = NB(\pi\ (\dfrac{d}{2})^2)\ (2\pi f)

\epsilon = (1)\ 1.4 \times 10^{-3}(\pi\ (\dfrac{7.5 \times 10^{-6}}{2})^2)\ (2\pi\times 60)

\epsilon = 2.96 \times 10^{-11} \ V

maximum emf that can generate around the perimeter of the cell \epsilon = 2.96 \times 10^{-11} \ V

5 0
3 years ago
You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between
Murljashka [212]

Answer:

a) v = 0.0496 m / s , b)  v = 0.0957 m / s

Explanation:

a) in this case we have an inelastic collision,

To solve these problems, the most important thing is to define the system formed by all the bodies, so that the forces during the crash have been internal and the amount of movement is conserved.

Therefore the system is made up of the ball and the player

initial instant. Before catching the ball

       p₀ = m v₁

final moment. After you have grabbed the ball

      p_{f} = (m + M) v

the moment is preserved

       po = p_{f}

       m v₁ = (m + M) v

       v = m / (m + M) v₁

let's calculate

      v = 0.405 / (0.405 + 69)   8.50

      v = 0.0496 m / s

in the same direction that the ball takes

b) In this case the ball bounces with a speed of V₂ = -7.80 m / s, the negative sign is because it is going in opposite directions

let's write the moment in two times

initial instant. Before the crash

       p₀ = m v₁

try end. Right after the crash

       p_{f} = m v₂ + M v

the moment is preserved

       p₀ = p_{f}

        m v₁ = m v₂ + M v

       v = m (v₁ -v₂) / M

       v = 0.405 /69   (8.50 - (7.80))

       v = 0.0957 m / s

in the initial direction of the ball

8 0
3 years ago
In 1976, the SR-71A, flying at 20 km altitude (T = –56 0C), set the official jet-powered aircraft speed record of 3530 km/hr (21
Lapatulllka [165]

To solve this problem we will apply the concepts related to the calculation of the speed of sound, the calculation of the Mach number and finally the calculation of the temperature at the front stagnation point. We will calculate the speed in international units as well as the temperature. With these values we will calculate the speed of the sound and the number of Mach. Finally we will calculate the temperature at the front stagnation point.

The altitude is,

z = 20km

And the velocity can be written as,

V = 3530km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V = 980.55m/s

From the properties of standard atmosphere at altitude z = 20km temperature is

T = 216.66K

k = 1.4

R = 287 J/kg

Velocity of sound at this altitude is

a = \sqrt{kRT}

a = \sqrt{(1.4)(287)(216.66)}

a = 295.049m/s

Then the Mach number

Ma = \frac{V}{a}

Ma = \frac{980.55}{296.049}

Ma = 3.312

So front stagnation temperature

T_0 = T(1+\frac{k-1}{2}Ma^2)

T_0 = (216.66)(1+\frac{1.4-1}{2}*3.312^2)

T_0 = 689.87K

Therefore the temperature at its front stagnation point is 689.87K

6 0
4 years ago
Which two layers make up the Earth's upper mantle?
Bad White [126]

Answer: The lithosphere and the asthenosphere

4 0
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