1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AveGali [126]
4 years ago
5

A common mistake that many managers tend to make is focusing on only one type of metric because they are easier to measure. Whic

h type of metric do they focus on?
Computers and Technology
1 answer:
Katarina [22]4 years ago
7 0

Answer:

The answer is "Efficiency MIS metrics".

Explanation:

Efficiency MIS indicators evaluate the performance of the MIS system, like capacity, processing rate, and device quality. It measures the tests of the impact of MIS on business and business systems, like consumer satisfaction and customer transfer.

  • It provides the ease of purchases as well as the desire to find knowledge, and it also managers the tend to make it only relies on a certain kind of measurement since it is easier to quantify.
  • The main objective of this system is used to improve routine operating efficiency.
You might be interested in
Zoe runs a sports media website that caters to fans of many different types of sports. She's starting a Google Display Ads campa
Alex

Answer:

Affinity Audiences allow her to reach sports enthusiasts.

Explanation:

Affinity Audiences are usually TV-style audiences normally designed with the aim of trying to connect advertisers with the type of customers they are searching for online at any point in time. Google Ads uses this feature via the browser history of the user and the time spent on pages and then associates the users browser with a category of interest.

8 0
3 years ago
What is the importance of technology in your life?Explain.
Ghella [55]

technology has been very important in my life because, it helps me with my daily struggles, helps with stress (social media), makes everything easier, also creates a more efficient way of learning and much more.

although this should be answered with your own thoughts and opinions, I provided mine if in any case that it helps

8 0
3 years ago
g Write a Racket function (process lst1 lst2) that processes the corresponding elements of the two lists and returns a list. If
blagie [28]

Answer:

  1. def process(lst1, lst2):
  2.    newList = []
  3.    for i in range(0, len(lst1)):
  4.        sum = lst1[i] + lst2[i]
  5.        newList.append(sum)
  6.    return newList
  7. list1 = [1, 3, 5, 7, 9]
  8. list2 = [2, 4, 6, 8, 10]
  9. print(process(list1, list2))

Explanation:

Firstly, create a function process that takes two input lists (Line 1). In the function, create a new list (Line 2). Use a for loop to traverse through the elements of the two lists and total up the corresponding elements and add the sum to the new list (Line 3 - 5). At last, return the new list (Line 6).

In the main program, create two sample list and use them as arguments to test the function process (Line 8 - 9). We shall get the output  [3, 7, 11, 15, 19].

8 0
4 years ago
Which device assists with medical imaging
masya89 [10]
MRI- Magnetic Resonance Imaging

        OR

USI- Ultrasound Imaging
5 0
3 years ago
Read 2 more answers
#include
rodikova [14]

Output

SORTED                                                                                                                                

4 7 10 69                                                                                                                              

                                                                                                                                     

SORTED                                                                                                                                

10 9 7 3                                                                                                                              

                                                                                                                                     

NOT SORTED                                                                                                                            

19 12 23 7                                                                                                                            

                                                                                                                                     

SORTED                                                                                                                                

5 5 5 5

Code

//The added part is in the bottom

#include <iostream>

using namespace std;

const int SIZE = 4;

bool isSorted (const int arr[], int size);

bool isNonDecreasing (const int arr[], int size);

bool isNonIncreasing (const int arr[], int size);

void printArr (const int arr[], int size);

int

main ()

{

 int test1[] = { 4, 7, 10, 69 };

 int test2[] = { 10, 9, 7, 3 };

 int test3[] = { 19, 12, 23, 7 };

 int test4[] = { 5, 5, 5, 5 };

 if (!isSorted (test1, SIZE))

   cout << "NOT ";

 cout << "SORTED" << endl;

 printArr (test1, SIZE);

 if (!isSorted (test2, SIZE))

   cout << "NOT ";

 cout << "SORTED" << endl;

 printArr (test2, SIZE);

 if (!isSorted (test3, SIZE))

   cout << "NOT ";

 cout << "SORTED" << endl;

 printArr (test3, SIZE);

 if (!isSorted (test4, SIZE))

   cout << "NOT ";

 cout << "SORTED" << endl;

 printArr (test4, SIZE);

 return 0;

}

bool

isSorted (const int arr[], int size)

{

//Added part

 if (isNonDecreasing (arr, size) || isNonIncreasing (arr, size))

   {

     return true;

   }

 else

   {

     return false;

   }

}

bool

isNonDecreasing (const int arr[], int size)

{

 for (int i = 0; i < (size - 1); i++)

   {

     if (arr[i] > arr[i + 1]) //It compares the n value with the n-1 value and output

{

  return false;

  break;

}

   }

 return true;

}

bool

isNonIncreasing (const int arr[], int size)

{

 for (int i = 0; i < (size - 1); i++)

   {

     if (arr[i] < arr[i + 1]) //It compares the n value with the n-1 value and output reautilization of previous function by replacing only “<”

{

  return false;

  break;

}

   }

 return true;

}

void

printArr (const int arr[], int size)

{

 for (int i = 0; i < size; i++)

   cout << arr[i] << " ";

 cout << endl << endl;

}

7 0
3 years ago
Other questions:
  • Styles are modified by using the Office clipboard in the Home tab. true or false
    5·2 answers
  • Kendall receives an email stating that a leading computer company is giving away free computers, asking her to forward the email
    15·1 answer
  • True/False: When you make a function call, the order of the arguments you send does not matter as long as the number of argument
    15·1 answer
  • Assuming that each of the resistors in the circuit shown in the figure above has a resistance value of 100 k ohms, what will be
    11·2 answers
  • Assume that a is an array of two or more integers, and that b and c are integers.
    13·1 answer
  • Enter a word: Good<br> Enter a word: morning<br> Good morning
    8·2 answers
  • HELP 10 POINTS
    5·1 answer
  • Explain the major innavotions made from the establishment of abacus​
    8·1 answer
  • 11. Explain different types of program control with suitable flow chart.<br> N
    15·1 answer
  • what option can be used to create vpn connections that can be distributed to users' computers so that vpn clients do not have to
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!