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Vadim26 [7]
2 years ago
11

Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. Round to the nea

rest tenths place.
I need help, please

Mathematics
1 answer:
Delvig [45]2 years ago
5 0

Answer:

so you multiply the 13 by 12. Then divid 12 by 2 to get 6 as the radius then use a calculator and type in 2(PIE SYMBOL) R. R=radius then whatever number you get cut it in half then subtract it from 13x12.

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1. Michael DeBakey is an important Texan. What is his contribution and what did he do that was important? Did he invent anything
Jobisdone [24]

Answer:

n 1932 DeBakey devised the “roller pump,” an essential component of the heart-lung machine that permitted open-heart surgery. He also developed an efficient method of correcting aortic aneurysms by grafting frozen blood vessels to replace diseased vessels.

Works written: The New Living Heart

Born: September 7, 1908, Lake Charles

Died: July 11, 2008

Step-by-step explanation:

4 0
3 years ago
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The graph below represents the total shipping cost of x items for four different companies
Lady_Fox [76]

Answer:

there was no graph, therefore i cant answer this

Step-by-step explanation:

6 0
3 years ago
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Does anyone understand this?. I also have to show my work.
snow_lady [41]

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

Step-by-step explanation:

Given equation is C=\frac{5}{9}(F -32)

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=0.

For F = 41.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(41 -32)

C=05

For F = 50.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(50 -32)

C=10

For F = 59.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=15

<em>Note: The figure shows a graph of given equation with points.</em>

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

<em>C=18.333333.</em>

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C=\frac{5}{9}(F -32)

0=\frac{5}{9}(F -32)

0=(F -32)

F=32 Temperature.

Ans D). Slope of the line C=\frac{5}{9}(F -32)

The slope of line is given by s= \frac{Y1-Y2}{X1-X2}

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= \frac{Y1-Y2}{X1-X2}

s= \frac{0-5}{32-41}

s= \frac{5}{9}

Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

7 0
3 years ago
Find f(x) if it is known that f(x-2)=2x-4
Nikolay [14]

Answer:

f=2

Step-by-step explanation:

f(x-2)=2x-4

divide x-2 to 2x-4

f=2

f(2-2)=4-4

3 0
3 years ago
Write an equation for the line that passes through (- 3, 5) and is parallel to y = - 6x + 1.
soldier1979 [14.2K]

Answer:

y-5 = -6(x+3) OR y = -6x-13

Step-by-step explanation:

Let's use slope-intercept form to solve this problem.

Slope intercept form is the following:

y-y1 = m(x-x1)

x1 and y1 are given by the point in the problem.

x1 = -3, y1 = 5.

m is given by the equation in the problem. Lines that are parallel have the same slope. Thus,

m = -6.

If we plug these values into the equation for slope intercept form, we get the following:

y-5 = -6(x-(-3)) which becomes y-5 = -6(x+3)

This is an acceptable answer to the problem. However, point-slope form is also a way it can be written.

y-5 = -6x-18

y = -6x-13

3 0
2 years ago
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