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marta [7]
3 years ago
12

A diatomic molecule shares three pairs of electrons. What type of bond is present in the molecule? A single covalent bond becaus

e each atom requires one more electron to complete its octet. A single covalent bond because each atom requires six more electrons to complete its octet. A triple covalent bond because each atom requires three more electrons to complete its octet. A triple covalent bond because each atom requires six more electrons to complete its octet.
Chemistry
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:

A triple covalent bond because each atom requires three more electrons to complete its octet.

Explanation:

VMariaS [17]3 years ago
3 0
<h3><u>Answer</u>;</h3>

A triple covalent bond because each atom requires three more electrons to complete its octet.

<h3><u>Explanation</u>;</h3>
  • A triple covalent bond is a covalent bond formed by atoms that share three pairs of electrons.
  • For example;<em><u> in a diatomic molecule such a nitrogen; A nitrogen atom has five valence electrons, which can be shown as one pair and three single electrons. </u></em>When combining with another nitrogen atom to form a diatomic molecule, the three single electrons on each atom combine to form three shared pairs of electrons.
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4.61 x 10^23

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Chemistry question.
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8 0
2 years ago
Why is an electron ejected when green light hits the metal?
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Explanation:

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3 years ago
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

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Mathematically:

\frac{V}{T}=const.

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V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

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3 years ago
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Answer: The electronic configuration of nitrogen is 1s2 2s2 2p3. Thus nitrogen has a half-filled p orbital, which is comparatively more stable. Thus the p orbital is the outermost orbital. To achieve a stable gas configuration, nitrogen needs to have a fulfilled p orbital.

Explanation: please mark brainlyest i really nead it

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2 years ago
Read 2 more answers
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