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marta [7]
3 years ago
12

A diatomic molecule shares three pairs of electrons. What type of bond is present in the molecule? A single covalent bond becaus

e each atom requires one more electron to complete its octet. A single covalent bond because each atom requires six more electrons to complete its octet. A triple covalent bond because each atom requires three more electrons to complete its octet. A triple covalent bond because each atom requires six more electrons to complete its octet.
Chemistry
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:

A triple covalent bond because each atom requires three more electrons to complete its octet.

Explanation:

VMariaS [17]3 years ago
3 0
<h3><u>Answer</u>;</h3>

A triple covalent bond because each atom requires three more electrons to complete its octet.

<h3><u>Explanation</u>;</h3>
  • A triple covalent bond is a covalent bond formed by atoms that share three pairs of electrons.
  • For example;<em><u> in a diatomic molecule such a nitrogen; A nitrogen atom has five valence electrons, which can be shown as one pair and three single electrons. </u></em>When combining with another nitrogen atom to form a diatomic molecule, the three single electrons on each atom combine to form three shared pairs of electrons.
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A sample of nitrogen occupies 10.0 liters at 25°C and 98.7 kPa. What would be the volume at 20°C and 102.7 kPa?
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To solve the problem, we assume the sample to be ideal. Then, we use the ideal gas equation which is expressed as PV = nRT. From the first condition of the nitrogen gas sample, we calculate the number of moles.

n = PV / RT
n = (98.7x 10^3 Pa x 0.01 m^3) / (8.314 Pa m^3/ mol K) x 298.15 K
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At the second condition, the number of moles stays the same however pressure and temperature was changed. So, the new volume is calculated as follows:

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7 0
3 years ago
For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.
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Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

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53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

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