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True [87]
3 years ago
13

4) If a person is riding a bike and want to slow down, they use the brakes. This is an example of which of the following?

Chemistry
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer: C A B

Explanation:

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Sea water is an electrolyte.<br> True<br> False
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If you are talking about just pure regular water, the answer is false. BUT, some salts dissolved IN WATER, can act as electrolytes. But regular water, no.
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3 years ago
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A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.
8_murik_8 [283]
<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>
  • According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
  • Mathematically, P\alpha \frac{1}{V}

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

P2=\frac{P1V1}{V2}

Replacing the known variables with the values;

P2=\frac{(101.5)(2.0L)}{0.25L}

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

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3 years ago
2 1.1.4 Quiz: Amplitude, Frequency, and Speed
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How do you name these compounds?
8090 [49]
1) is right
2) lead(ii) phosphate
3) iron(iii)sulfate
4) lead(ii)oxide
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8 0
3 years ago
An ideal gas at a given initial state expands to a fixed final volume. would the work be greater if the expansion occurs at cons
crimeas [40]

Answer:

Constant pressure

Explanation:

At constant pressure,

w = -p\Delta V = -p(V_{f} - V_{i})

At constant temperature,

w = -RT \ln \left(\dfrac{V_{f}}{V_{i}} \right)

1 mol of an ideal gas at STP has a volume of 22.71 L.

Let's compare the work done as it expands under each condition from an initial volume of 22.71 L.

Isobaric expansion

w = -100p(V_{2} - 22.71}); \text{(1 bar$\cdot$L = 100 J)}

A plot of -w vs V₂ gives a straight line (red) with a constant slope of 100 J/L as in the diagram below (Note that w is work done on the system, so -w is the work done by the system). \

Isothermal expansion

w= -8.314 \times 273.15 \ln \left(\dfrac{V_{f}}{22.71} \right)\\\\= -2271 \left( \ln V_{f} -\ln22.71 \right)\\= -2271 \left(\ln V_{f} - 3.123 \right)\\= 7092 - 2271\ln V_{f}

A plot of -w vs V₂ is a logarithmic curve. Its slope starts at 100 J/mol but decreases as the volume increases (the blue curve below).

Thus, the work done during an expansion at constant pressure is greater than if the system is at constant temperature.

4 0
3 years ago
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