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3 years ago

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If two balls have the same volume, but ball A has twice as much mass as ball B, which one will have the greater density? ball A,

ball B, Their densities are equal.
If ball C is 3 times the volume of ball D and ball D has 1/3 the mass of ball C, which has the greater density? ball C, ball D, Their densities are equal.

If two balls have the same mass, but ball P is twice as large as ball Q, which one will have the greater density? ball P, ball Q, Their densities are equal.

If ball X is twice as big as ball Y and weighs only half as much as ball Y, then which one will have the greater density? ball X, ball Y, Their densities are the same.

2 answers:

castortr0y [4]3 years ago

7 0

Answer:

The correct ansers are

Slot 1 is Ball A

Slot 2 is there deseties are equal

Slot 3 is Ball Q

Slot 4 is Ball Y

Explanation:

Took the asingment 2020 Edgeunuty

PLZ GIVE BRAINLIESt

rewona [7]3 years ago

5 0

Density (D) is defined as the amount or mass (m) of a substance present in a unit volume(V). It can be expressed mathematically as:

Density = Mass/Volume

i.e. D = m/V -------(1)

Units: g/cm3

a)

If m1, V1 and D1 = mass, volume and density respectively of ball A

m2, V2 and D2 = mass, volume and density respectively of ball B

It is given that: V1 = V2; but m1 = 2m2

Based on equation (1) we have:

D1/D2 = (m1/V1)* (V2/m2) = (2m2/V2)*(V2/m2) = 2

Thus, density of ball A is twice that of B.

Ans: Ball A will have a greater density than B

b)

If m1, V1 and D1 = mass, volume and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

It is given that:

V1 = 3V2 and m2 = 1/3(m1) i.e m1 = 3m2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (3m2/3V2)*(V2/m2) = 1

Thus, D1 = D2

Ans: Their densities are equal

c)

If m1, V1 and D1 = mass, volume and density respectively of ball P

m2, V2 and D2 = mass, volume and density respectively of ball Q

It is given that:

m1 = m2 but V1 = 2V2

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = (m2/2V2)*(V2/m2) = 1/2

Thus, D1 = 1/2(D2)

Ans: Ball Q will have a greater density.

d)

If m1, V1 and D1 = mass, volume and density respectively of ball X

m2, V2 and D2 = mass, volume and density respectively of ball Y

It is given that:

V1 = 2V2 and m1 = 1/2(m2)

Therefore,

D1/D2 = (m1/V1)* (V2/m2) = ((1/2(m2)/2V2)*(V2/m2) = 1/4

Thus, D1 = 1/4(D2)

Ans: Ball Y will have a greater density.

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What color has a wavelength of 6.49*10^23?

Yakvenalex [24]

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In short, Your Answer would be: Orange

Hope this helps!

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3 years ago

Read 2 more answers

What is the frequency of the light with a wavelength of 4.90x10^-7 m

docker41 [41]

Answer: $6.12\times 10^{14}$ Hz

Explanation: Recall the formula for the speed of light is

$c=\lambda v$

where $c$ is the speed of light, $\lambda$ is the wavelength, and $v$ is the frequency. Assuming this takes place in a vacuum, $c=3.00\times 10^8$ m/s. Now we can solve for frequency

$c=\lambda v$

$3.00\times 10^8 = 4.90\times 10^{-7}\cdot v$

$v = \frac{3.00\times 10^8}{4.90\times 10^{-7}}$

$v =6.12\times 10^{14}$ (rounding to 3 sig figs)

Thus, the frequencyis $6.12\times 10^{14}$ Hz.

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3 years ago

an atom has an atomic number of 9 a mass number of 19 and an electron configuration of 2-6-1 explain why the number of electrons

sukhopar [10]

You can tell that the atom is in the excited state because:

- Electron configuration should follow the 2-8-8-2 rule, meaning that the inner shell should be filled before the next shell can start holding electrons.

- Instead of the atom's electron configuration being in the ground state at 2-8-8-1, electrons from the second shell have jumped to the third.

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3 years ago

You have a stock solution that is 226mg/mL and you need 10mL of a working solution that is 15mg/mL. What is the volume of stock

xenn [34]

Answer: 0.67 ml

Explanation:

According to the dilution law,

$C_1V_1=C_2V_2$

where,

$C_1$ = concentration of stock solution = 226 mg/ml

$V_1$ = volume of stock solution = ?

$C_2$ = concentration of working solution= 15 mg/ml

$V_2$ = volume of working solution= 10 ml

Putting in the values we get:

$226mg/ml\times V_1ml=15mg/ml\times 10ml$

$V_1=0.67ml$

Thus volume of stock solution needed to dilute to have 10mL of working solution at the above concentration is 0.67 ml

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3 years ago

Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74

katovenus [111]

Answer:

D

Explanation:

The amount of energy released or absorbed is equal the product of the mass, the specific heat capacity and the temperature change. The temperature change being the difference between the final and initial temperature.

Q = mc∆T

Q = heat energy (Joules, J) m = mass of a substance (kg) c = specific heat (units J/g∙K)

∆ is a symbol meaning "the change in" ∆T = change in temperature (Kelvins, K)

From the data provided in the question, we can deduce that:

Q = 16.7KJ = 16,700J

m = 225g

c = 1.74J/g.k

For the temperature, let the final temperature be f. This means our ∆T = f - 20

16,700 = 225 * 1.74 * (f - 20)

16700 = 391.5 (f - 20)

f - 20 = 16700/391.5

f - 20 = 42.7

f = 20 + 42.7 = 62.7

Hence the final temperature is 62.7 degrees Celsius

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3 years ago