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aniked [119]
4 years ago
13

I’m struggling with dimensional analysis in chemistry! Will someone please help me with .74 Kcal/min to cal/sec ? Explain and gi

ve answer please I need a deep explanation. I’ve watched videos and nothing seems to show metric conversions which are on my worksheet too.

Chemistry
1 answer:
valina [46]4 years ago
3 0

Answer:

            12.33 cal/sec

Explanation:

As we know,

                          1 Kcal  =  1000 cal

So,

                     0.74 Kcal  =  X cal

Solving for X,

                      X =  (0.74 Kcal × 1000 cal) ÷ 1 Kcal

                      X =  740 cal

Also we know that,

                      1 Minute  =  60 Seconds

Therefore, in order to derive cal/sec unit replace 0.74 Kcal by 740 cal and 1 min by 60 sec in given unit as,

                                       = 740 cal / 60 sec

                                       = 12.33 cal/sec

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3 years ago
Suppose two 200.0-L tanks are to be filled separately with the gases helium and hydrogen. What mass of each gas is needed to pro
Aneli [31]

Answer:

Mass of helium  = 4426.9524 g

Mass of hydrogen gas = 2213.4762 g

Explanation:

Pressure = 135 atm

Temperature = 24 °C

Volume = 200 L

Number of moles = ?

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (24 + 273.15) K = 297.15 K  

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

135 atm × 200 L = n × 0.0821 L.atm/K.mol × 297.15 K  

⇒n = 1106.7381 moles

<u>For helium gas:</u>

Molar mass = 4 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

1106.7381= \frac{Mass}{4}

Mass= 4426.9524\ g

<u>For hydrogen gas:</u>

Molar mass = 2 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

1106.7381= \frac{Mass}{2}

Mass= 2213.4762\ g

4 0
4 years ago
How many atoms are present in 3.1 moles of copper?
ozzi

Answer:

<h2>1.8662 × 10²⁴ atoms</h2>

Explanation:

The number of atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

N = 3.1 × 6.02 × 10²³

We have the final answer as

<h3>1.8662 × 10²⁴ atoms</h3>

Hope this helps you

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3 years ago
How does a solution differ from a heterogeneous mixture?
belka [17]
Both are considered mixtures<span> - that is, they are made up of two or more pure substances. ... A </span>heterogeneous mixture<span> appears to be made of </span>different<span>substances. A </span>solution<span> appears the same throughout. In the fluid phase (gas or liquid, or any combination of those) a </span>solution<span> is transparent (thought not colourless). hope that helps</span>
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4 years ago
Consider the following reaction:2NOBr(g) 2NO(g) + Br2(g)If 0.412 moles of NOBr(g), 0.678 moles of NO, and 0.224 moles of Br2 are
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Answer: K_c=0.0587M

Explanation: The given chemical reaction is:

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Equilibrium constant (Kc) in general is written as:

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Note:- Coefficients are written as their powers

So, the Kc expression for the above reaction will be:

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Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.

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[NO]=\frac{0.678mol}{10.3L}   = 0.0658 M

[Br_2]=\frac{0.224mol}{10.3L}   = 0.0217 M

Plug in the values in the equilibrium expression to calculate Kc.

K_c=\frac{(0.0658M)^2(0.0217M)}{(0.040M)^2}

K_c=0.0587M

4 0
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