A gas system contains 2.00 moles of O2 and CO2 gas, has an initial temperature of 25.0 oC and is under 1.00 atm of pressure. If
1 answer:
Answer:
Explanation:
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In this case, by bearing to to mind the given conditions, it is firstly possible to determine the initial volume of the closed system via the ideal gas equation:
Which is V1 in the Charles' law:
And of course, T1 is 298.15 (25+273.15). Therefore, by solving for V2 as the final volume, we obtain:
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The half-life of cobalt-60 is 5.26 years. After 10.52 years, 5 grams of a 20-gram sample will remain is TRUE
<u>Explanation:</u>
Mass of cobalt = 20 g
Half-life = 5.26 years
Mass remains after 10.52 years = 5 g
This can be solved by using given below formula,
= initial mass
t = number of years from when the mass was m_0
m(t) = remaining mass after t years
Number of half-lives =
Number of half-lives =
Number of half-lives = 2
At time zero = 20 g
At first half-life = = 10 g
At second half life = = 5 g
The given statement is true.
Answer:
Explanation:
From the given information:
A → B k₁
B → A k₂
B + C → D k₃
The rate law =
Using steady-state approximation;
From equation (1), we have:
when the pressure is high;
k₂ << k₃[C]
k₂ >> k₃[C]
Answer:
so the number of molecules in 8 moles of water is 4.8176×10^24
Explanation:
number of moles=8moles
avogadro's number=6.022×10²³
number of molecules=?
as we know that
substituting the equation
number of moles × avogdro's number=number of molecules
number of molecules=8moles×6.022×10²³
number of molecules=4.8176×10^24
i hope this will help you :)