All categories

2 years ago

Sublimation is snow or ice changing to a gas without melting. What must happen to the molecules for this to happen?

1 answer:

6 0

Answer:Sublimation is the conversion between the solid and the gaseous phases of matter, with no intermediate liquid stage. For those of us interested in the water cycle, sublimation is most often used to describe the process of snow and ice changing into water vapor in the air without first melting into water.

Explanation:

You might be interested in

For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a cl

Usimov [2.4K]

Answer: The approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

$K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

$1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

On reversing the reaction:

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

initial pressure 4.00atm 2.00 atm 0

eqm (4.00-2x)atm (2.00-x) atm 2x atm

$K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}$

$K_p'=\frac{1}{K_p}=0.67\times 10^5$

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

$0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}$

$x=1.96$

$[H_2S]=2x=2\times 1.96=3.92 atm$

Thus approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

3 0

3 years ago

Compare the electron-dot formulas of CH4 and H2O. Why do these molecules have approximately the same bond angles but different m

AVprozaik [17]

Because of the difference in the # of mollecules

4 0

3 years ago

Read 2 more answers

What is a rock that forms when pressure, temperature, or chemical processes change an existing rock

Tamiku [17]

I think that is called a Metamorphic rock.

3 0

2 years ago

Read 2 more answers

Image included

Romashka [77]

Answer:1

Explanation:cause castle told me

4 0

2 years ago

The radioisotope potassium-40 decays to argon-40 by positron emission with a half-life of 1.3 Ã 109 yr. A sample of moon rock wa

Aloiza [94]

Answer:

4.66 x 10^8 yr

Explanation:

The age of the rock can be calculated using the equation:

ln (N/N₀) = - kt where N is the quantiy of radioisotope decayed and N₀ is the initially quantity present of the radioisotope; k is the decay constant, and t is the time.

Now from the data , we have 78 argon-40 atoms for every 22 potassium-40 atoms, we can deduce that originally we had 22 + 78 = 100 atoms of potassium-40 so this is our N₀.

When we look at the equation, we see that k is unknown, but we can calculate it from the half-life which is given by the equation:

k = 0.693/ t half-life = 0.693/ 1.3 x 10⁹ yr = 5.33 x 10⁻¹⁰ yr⁻¹

Now we are in position to answer the question.

ln ( 78/100 ) = - (5.33 x 10⁻¹⁰ yr⁻¹ ) t

- 0.249 = - 5.33 x 10⁻¹⁰ yr⁻¹ t

0.249/ 5.33 x 10⁻¹⁰ yr⁻¹ = t

4.66 x 10^8 yr

8 0

3 years ago