Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
The given functions are
Now these are exponential curves and the bases for the functions are 3.5 & 1.5
Also the graph of g(x) is between f(x) & h(x)
Hence the value of base called the scale factor must be between 3.5 & 1.5.
4 & 5 are more than 3.5
0.9 is smaller than 1.5
But π = 3.14 lies between 3.5 & 1.5.
Hence the only option which can represent the graph of g(x) is
Option D) is the right answer
200 dollars like the answer please
Answer:
Inverse of -5-9x/x-6
Step-by-step explanation:
Steps:
1: Interchange the variables x and y.
x=6y-5/y+9
2: Solve x = 6y-5/y+9 for y
3: Multiply both sides by y+9
4: Simplify and Expand
5: Subtract 9x from both sides.
6: Simplify and Subtract y from both sides then Simplify again
7: Divide both sides by x-6
Answer: Inverse of -5-9x/x-6
<em><u>Hope this helps.</u></em>
Sin (Angle) = Opposite / Hypotenuse
Sin (X) = 8/17
X = Arcsin(8/17)
X = 28.07 degrees.
