Question

A 20 cm long spring is attached to a wall. The spring stretches to a length of 22 cm when you pull on it with a force of 100 n. What is the spring constant

Answer 1

Answer:

5000 N/m

Explanation:

Hooke's law for the spring is

$F = k \Delta x$

where here we have

F = 100 N is the force applied to the spring

k is the spring constant

$\Delta x = 22 cm - 20 cm = 2 cm = 0.02 m$ is the stretching of the spring with respect to its equilibrium position

Solving the equation for k, we find the spring constant:

$k=\frac{F}{\Delta x}=\frac{100 N}{0.02 m}=5000 N/m$