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ELEN [110]
3 years ago
9

7 One lb of Refrigerant 134a contained within a piston–cylinder assembly undergoes a process from a state where the temperature

is 60F and the refrigerant is saturated liquid to a state where the pressure is 140 lbf/in 2 and quality is 50%. Determine the change in specific entropy of the refrigerant, in Btu/lbR. Can this process be accomplished adiabatically?
Physics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb ^ {\circ} R}

Explanation:

A) In order to solve the table it is necessary to consult tables A11-E and A10E for refrigerant R134-a

In this way we obtain that:

S_1 = S_f = 0.0648 \frac {BTU} {Lb. ^ {\circ} R}

In this way,

S_2 = S_f + x_2 (S_g-S_f) = 0.0902 + 0.5 (0.2161-0.0902)

S_2 = 0.15315 \frac {BTU} {Lb ^ {\circ} R}

In this way the entropy change is,

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb. ^ {\°} R}

B) Whenever entropy yields a positive result, the process can be carried out adiabatically.

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electrical conduction through a gas in an applied electric field

Explanation:

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3 years ago
Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has
k0ka [10]

Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

8 0
3 years ago
Match each action to its result. The strength of the electromagnet increases. The electromagnet turns off. The poles of the elec
IceJOKER [234]

Answer:

1) The strength of the electromagnet increases   →   Place a magnetic core inside the coil of wire

2) The electromagnet turns off    →    Turn off the battery supply

3) The poles of the electromagnet reverse     →    Change the direction in which the current flows

Explanation:

when current passes through a coil it behaves a an electromagnet.

Magnetic field strength is given by

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N is no of turns and

I is the current through coil

μ is permeability of the medium or core in the coil.

1). Magnetic core increase permeability μ so it will strengthen magnetic field:

B = <u>μ</u> N I

2). When the battery turns off current becomes zeroi.e I=0

So B = μ N * 0

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so electromagnet turns off

3). Direction of magnetic field can be determine by right hand rule, i.e curl the fingers in the direction of current, thumb will point in the direction of north pole.

so changing current direction will change direction of magnetic field.

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3 years ago
When you place leftover food in the refrigerator, what kind of energy do you
Verdich [7]
I believe the correct answer is D
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2 years ago
Read 2 more answers
Gravitational forces is ------ force​
mel-nik [20]

Answer:

Gravitational force is <u>noncontact</u> force

Explanation:

Contact force occurs due to the contact between two different objects. Non-contact force occurs due to either attraction or repulsion between two objects such that there is no contact between these objects. There is no field linked with the contact force. ... Gravitational force is an example of a non-contact force.

7 0
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