If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
1 answer:
The magnitude of the electric field is
Explanation:
The electrostatic force experienced by an electric charge immersed in an electric field is given by
where:
q is the charge of the particle
E is the strength of the electric field
F is the force
In this problem, we have:
is the charge of the particle
is the force
Therefore, we can find the electric field by solving the equation for E:
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Answer:
c. nine times as low.
Explanation:
Sound intensity is defined as the acoustic power transferred by a sound wave per unit of normal area to the direction of propagation:
Since the sound wave has a spherical wavefront of radius r, then the area is given by:
Here r is the distance from the source of the sound. Thus sound intensity decreases as:
Since the acceleration is constant, the average velocity is simply the average of the initial and final velocities of the body:
We can proof that the distance covered by the body moving at constant average velocity is equal to the distance covered by the body moving at constant acceleration a:
- body moving at constant velocity : distance is given by
- body moving at constant acceleration : distance is given by