Answer:
The period of Y increases by a factor of
with respect to the period of X
Step-by-step explanation:
The equation
shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?
For the planet Y:
For planet X:
To know the factor of aumeto we compared
with
We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:
So
Then, the period of Y increases by a factor of
with respect to the period of X
Answer: -3 , 3
Step-by-step explanation:
thank me later;)
Answer:
a=30
b=150
c=30
Step-by-step explanation:
Answer: 6,048
Step-by-step explanation:
15,000-8,952=6,048
The original function is
f(x)=√x
As this is condition for √x function, x≥ 0
So,
Domain= [0, infinity)
Range= [0, infinity)
After the reflection across x-axis and y-axis, we get a function,
g(x)=-√-x
-x≥ 0 means x≤ 0,
So,
Domain= (-infinity, 0]
Range= (-infinity, 0]
From this you can see that
-The only value that is in the domains of both functions is 0.
-The range of g(x) is all values less than or equal to 0.
only these points are correct and all other points are wrong.
See the attached graphs for both functions.