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dalvyx [7]
3 years ago
8

The "opposite" of ionization energy is

Physics
1 answer:
Marianna [84]3 years ago
6 0
The opposite of ionization energy is B, electronegativity. In short, we can define ionization energy as the amount of energy required to remove one electron from the outermost valence shell from an atom. Conversely, we can define electronegativity as an atom's "willingness" to accept one electron. 

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A comet is a
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The answer is D. Small object made of ice and dust that orbits the Sun and forms a coma as it approaches the Sun.
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In Paragraph 3 of this passage, what clues help you know the meaning of the word
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The answer is d because you have to make sure that everything is right
4 0
3 years ago
How many cubic feet are in a 55-gallon drum?
san4es73 [151]
1 gallon = 231 cubic inches
1 cubic foot = 1728 cubic inches

                       (55 gal) x (231 in³/gal) x (1 ft³/1728 in³)

                   =    (55 x 231 / 1728)  ft³

                   =         7.352 cubic feet       (rounded)  
5 0
3 years ago
Calculate the AMA of an access ramp if it takes 255 N of force to push a person in a wheelchair having a combined weight of 764
Andreyy89
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Here, Weight = 764 N
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Hope this helps!
7 0
3 years ago
An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.
Pachacha [2.7K]

Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

We need to calculate the object distance

u -v= d

u=71+26=97\ cm

We need to calculate the focal length

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-26}+\dfrac{1}{97}

\dfrac{1}{f}=-\dfrac{71}{2522}

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(B). Given that,

Object distance = 95 cm

Focal length = 29 cm

We need to calculate the distance of the image

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value in to the formula

\dfrac{1}{-29}=\dfrac{1}{v}-\dfrac{1}{95}

\dfrac{1}{v}=\dfrac{1}{-29}-\dfrac{1}{95}

\dfrac{1}{v}=-\dfrac{124}{2755}

v=-22.21\ cm

We need to calculate the magnification

Using formula of magnification

m=\dfrac{v}{u}

m=\dfrac{22.21}{95}

m=0.233

The magnification is 0.233.

The image is virtual.

Hence, This is the required solution.

4 0
3 years ago
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