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zheka24 [161]
3 years ago
10

1. A recipe calls for cups of flour, cup of white sugar, and cup of brown sugar. The recipe makes 6 servings.

Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0
For (A) take 6÷ 1 1/2= 4 cups. There are 4 cups of flour per serving. For (B) add the total cups of white and brown sugar, then, divide that number by 6. There are 8 cups of white sugar per serving ( 6÷ 3/4=8 cups). And there are 18 cups of brown sugar per serving ( 6÷ 1/3= 18 cups). So, therefore there are 26 cups of white and Brown sugar per serving. For (C) take 9 divided by 1 1/2 cups of flour , to see how many cups per serving, then take 6 divide by 1 1/2= 4 cups.
So, 9÷1 1/2= 6 cups and 6÷ 1 1/2= 4 cups 6-4=2 cups . You would need two more cups of flour for the modified recipe than you would need for the original recipe.
Feliz [49]3 years ago
7 0

Answer:

abc

Step-by-step explanation:

A=4  B= 26 C= 4 and 2

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Mademuasel [1]

Answer:

12/5

Step-by-step explanation:

Tangent = opposite/ adjacent

5 0
3 years ago
Consider the following function. f(x) = 2x3 + 9x2 − 24x (a) Find the critical numbers of f. (Enter your answers as a comma-separ
viktelen [127]

Answer:

(a) The critical number of f(x) are x=-4, 1

(b)

  • Increasing for (-\infty, -4)
  • Decreasing for (-4, 1)
  • Increasing for  (1, \infty)

(c)

  • relative maximum (-4, 112)
  • relative minimum (1, -13)

Step-by-step explanation:

(a) The critical numbers of a function are given by finding the roots of the first derivative of the function or the values where the first derivative does not exist. Since the function is a polynomial, its domain and the domain of its derivatives is (-\infty, \infty). Thus:

\frac{df(x)}{dx}  = \frac{d(2x^3+9x^2-24x)}{dx} =6 x^2+18x -24\\6 x^2+18x -24=0\\\boxed{x=-4, x=1}

(b)

  • A function f(x) defined on an interval is monotone increasing on (a, b) if for every x_1, x_2 \in (a, b): x_1 implies f(x_1)
  • A function f(x) defined on an interval is monotone decreasing on (a, b) if for every x_1, x_2 \in (a, b): x_1 implies f(x_1)>f(x_2)

Combining  the domain (-\infty, \infty) with the critical numbers we have the intervals (-\infty, -4), (-4, 1) and (1, \infty). Note that any of the points are included, in the case of the infinity it is by definition and the critical number are never included because the function monotony is not defined in the critical points, i.e. it is not monotone increasing or decreasing. Now, let's check for the monotony in each interval, for this, we check for the sign of the first derivative in each interval. Evaluating in each interval the first derivative (one point is enough), we obtain the monotony of the function to be:

  • Increasing for (-\infty, -4)
  • Decreasing for (-4, 1)
  • Increasing for  (1, \infty)

(c) From the values obtained in (a) so the relative extremum are the points (-4, 112) and (1, -13). The y-values are found by evaluating the critical numbers in the original function. Since the first derivative decreases after passing through  x=-4 and increases after passing through the point x=1 we have:

  • relative maximum (-4, 112)
  • relative minimum (1, -13)

3 0
4 years ago
Help please!!!
katovenus [111]

Answer:

x = \frac{7+\sqrt{47}\times i }{4}

Step-by-step explanation:

<u>To solve quadratic systems,we always substitute one variable in terms if the other and then solve the equation.</u>

x + 2y = 6                                 ---------------(1)

y - 5 = (x-2)^{2}         ---------------(2)

y = (x-2)^{2} + 5         ---------------(3)

Substitute (3) in (1) ,

x + 2( (x-2)^{2} + 5 ) = 6

(a + b)^{2} =a^{2} + 2ab + b^{2}

x + 2( x^{2} - 4x + 4 + 5 ) = 6

2x^{2} - 7x + 12=0      --------------(4)

The roots of the quadratic equation ax^{2}  +bx+c is

x = \frac{(-b) + \sqrt{(-b)^{2}-4 \times ac }  }{2 \times a}  -----------(5)

According to equation (5),solution of (4) is

x =  \frac{7 + \sqrt{(-7)^{2}-4 \times 24 }  }{2 \times 2}

x =  \frac{7+\sqrt{49-96}}{4}

x = \frac{7+\sqrt{47}\times i }{4}

 

4 0
3 years ago
Find the quartic function that is the best fit for the data in the following table.
Nikitich [7]

Answer:

hdhdhd

jdnffjfbjffbkfbfkfbfifoff

7 0
2 years ago
What would the domain and range of this graph be? In interval form, if it can be.
skad [1K]

Answer:

Step-by-step explanation:

Domain is the x values.  The interval of x-values that the function encompasses are from 0 inclusive to 7 exclusive.  In interval notation that is [0, 7).  The range is the y values.  The interval of y-values that the function encompasses are from what looks like -2 to 4.  In interval notation that is [-2, 4].  The domain goes from the lowest x-value to the highest; the range goes from the lowest y-value to the highest.

6 0
3 years ago
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