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Darya [45]
3 years ago
12

A chemist has 12 liters of a 25% acid solution. how many liters of water must be added to obtain a 20% acid solution?

Chemistry
1 answer:
NemiM [27]3 years ago
4 0
Three liters of water
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Living organisms contain carbon compounds.
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Living organisms do contain carbon compounds. This is true.

Explanation:

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An allylic carbocation is an example of a(n) _____ system. (select all that apply.)
DerKrebs [107]

An allylic carbocation is an example of a system that is:

  • delocalized
  • conjugated.

<h3>What is allylic carbocation?</h3>

An allylic carbocation is a resonance-stabilized carbocation with a formal charge of +1 on an allylic carbon in each of the two resonance forms.

Thus, it is correct to state that:

An allylic carbocation is an example of a system that is:

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brainly.com/question/16258022
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Full Question:

An allylic carbocation is an example of a(n) _______ system. (Select all that apply.)

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6 0
1 year ago
The first periodic table was organized according to atomic mass, but the current periodic table is arranged according to atomic
MrMuchimi

Answer: Atomic mass is associated with the number of neutrons and protons that are present in a particular nucleus of an element. Atomic number is usually the number of protons present in an element's nucleus. It is the average weight of an element. It is the total number of nucleons in the atom's nucleus.

Assuming there were errors in atomic masses, Mendeleev placed certain elements not in order of increasing atomic mass so that they could fit into the proper groups (similar elements have similar properties) of his periodic table.

- Have a nice day :)

8 0
3 years ago
How many grams of oxygen is needed to completely react with 9.30 moles of aluminum
Orlov [11]
Balanced chemical equation:

* moles of oxygen

4 Al + 3 O2 = 2 Al2O3

4 moles Al -------------- 3 moles O2
9.30 moles Al ---------- moles O2

moles O2 = 9.30 * 3 / 4

moles O2 = 27.9 / 4 => 6.975 moles of O2

Therefore:

Molar mass O2 = 31.9988 g/mol

n = m / mm

6.975 = m / 31.9988

m = 6.975 * 31.9988

m = 223.19 of O2


5 0
3 years ago
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