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Tatiana [17]
3 years ago
6

Compare and contrast the use of U-238 and C-14 in absolute age dating

Chemistry
2 answers:
Talja [164]3 years ago
7 0

Carbon-14 and Uranium-238 have something we call a half live, which is basically a known time period for it to change half of its C-14 or U-238 radioactively decay. Since we know how long that is 5730 years for Carbon-14 for half a sample to deteriorate, than we can figure out how old it is.



gizmo_the_mogwai [7]3 years ago
7 0

Answer:

Explained

Explanation:

Carbon dating C-14 is done to find the age of relatively younger fossils and rocks.Half life of C-14  is only 5700 years and can only be used to date fossils of about 50,000 years old. Where as Uranium-238 has half life of about 4.5 billion years. If 50% of U-238 is left in sample it means that the sample is 4.5 billion year old. It is to be noted that no fossils contain U-238 in it. It is contained only in the igneous and volcanic rocks. So no fossils can be dated using U-238.

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Sedaia [141]

Radio active decay reactions follow first order rate kinetics.

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t_{\frac{1}{2}} =\frac{ln 2}{k}

t_{\frac{1}{2}} = \frac{0.693}{k}

Where k is the decay constant

b) Finding out the decay constant for the decay of C-14 isotope:

Decay constant (k) = \frac{0.693}{t_{\frac{1}{2}}}

k = \frac{0.693}{5230 years}

k = 1.325 * 10^{-4} yr^{-1}

c) Finding the age of the sample :

35 % of the radiocarbon is present currently.

The first order rate equation is,

[A] = [A_{0}]e^{-kt}

\frac{[A]}{[A_{0}]} = e^{-kt}

\frac{35}{100} = e^{-(1.325 *10^{-4})t}

ln(0.35) = -(1.325 *10^{-4})(t)

t = 7923 years

Therefore, age of the sample is 7923 years.

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3 years ago
How is gas different from a liquid
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4 0
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nikdorinn [45]

Answer:

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Explanation:

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3 years ago
What concentration of monosodium phosphate would be required to make a solution of pH 7.4 with 0.2 M disodium phosphate ( pKa
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Answer:

The concentration of monosodium phosphate is 0.1262M

Explanation:

The buffer of H₂PO₄⁻ / HPO₄²⁻ (Monobasic phosphate and dibasic phosphate has a pKa of 7.2

To determine the pH you must use Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] is molarity of the conjugate base of the weak acid, [HA].</em>

For H₂PO₄⁻ / HPO₄⁻ buffer:

pH = 7.2 + log [HPO₄⁻² ] / [H₂PO₄⁻]

As molarity of the dibasic phosphate is 0.2M and you want a pH of 7.4:

7.4 = 7.2 + log [0.2] / [H₂PO₄⁻]

0.2 = log [0.2] / [H₂PO₄⁻]

1.58489 = [0.2] / [H₂PO₄⁻]

[H₂PO₄⁻] = 0.1262M

<h3>The concentration of monosodium phosphate is 0.1262M</h3>

<em />

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What product of the krebs cycle is considered a waste product of the reaction?
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