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Semenov [28]
3 years ago
9

Find three consecutive odd integers such that 5 times the third is 94 than the second

Mathematics
1 answer:
IrinaK [193]3 years ago
3 0
------------------------------------------------------------
Define the numbers
------------------------------------------------------------
First the first odd integer be x.
1st odd = x
2nd odd = x + 2
3rd odd = x + 4

------------------------------------------------------------
Form the equation and solve for x
------------------------------------------------------------
5(x + 4) - 94 = x + 2
5x + 20 - 94 = x + 2
5x - 74 = x + 2
5x - x = 2 + 74
4x = 76
x = 19

------------------------------------------------------------
Find the 3 consecutive integers
------------------------------------------------------------
1st = x = 19
2nd = x + 2 = 19 + 2 = 21
3rd = x + 4 = 19 + 4 = 23

------------------------------------------------------------
Answer: The 3 consecutive odd numbers are 19, 21 and 23
------------------------------------------------------------

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This question is incomplete

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