Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Yes I would say. if I am wrong I am sorry
Answer:
5 units
Step-by-step explanation:
Step one:
Given data
Le the first number be x
and the second number be y
So
x*y= 10-----------------1
and
x+y= 7-----------------2
from eqn 1
x= 10/y
put x= 10/y in eqn 2
cross multiply we have
rearrange
the factors of the quadratic expression are
-5 and -2
The longest side is 5 units
Answer:
A, B, E
Step-by-step explanation:
20 remainder 11 or 20 11/20 is the answer to the ?
