Find three consecutive odd integers such that 5 times the third is 94 than the second

1 answer:

3 0

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Define the numbers
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First the first odd integer be x.
1st odd = x
2nd odd = x + 2
3rd odd = x + 4

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Form the equation and solve for x
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5(x + 4) - 94 = x + 2
5x + 20 - 94 = x + 2
5x - 74 = x + 2
5x - x = 2 + 74
4x = 76
x = 19

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Find the 3 consecutive integers
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1st = x = 19
2nd = x + 2 = 19 + 2 = 21
3rd = x + 4 = 19 + 4 = 23

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Answer: The 3 consecutive odd numbers are 19, 21 and 23
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