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galina1969 [7]
3 years ago
9

A circular wire loop of radius 12.1 cm carries a current of 2.16 A. It is placed so that the normal to its plane makes an angle

of 56.3° with a uniform magnetic field of magnitude 11.4 T.
(a) Calculate the magnitude of the magnetic dipole moment of the loop in amperes-square meters.
(b) What is the magnitude of the torque acting on the loop?
Physics
1 answer:
notsponge [240]3 years ago
5 0

To develop this problem we will apply two concepts of electromagnetic physics. The first is the magnetic dipole moment which is defined as the product between the current and the area, and the other is the torque as a function of the magnetic field. Both are described below

The magnetic dipole moment is defined as,

M = IA

Here,

I = Current

A = Area

At the same time the Torque acting on the loop is given as,

\tau = BIASin\theta

Here,

B = Magnitude of the magnetic field

\theta = Angle between magnetic field and the normal to the plane

PART A) The radius of the circular loop is,

r  = 12.1*10^{-2}m

Using the expression of the area in a circle and replacing it in the definition of the magnetic dipole moment we have

M = IA

M = I (\pi r^2)

M = (2.16A)(\pi (12.1*10^{-2})^2)

M = 0.099A\cdot m^2

PART B) Using the expression for torque we now have the data of all the variables, therefore replacing them

\tau = BIA sin\theta

\tau = (11.4T)(2.16A)(\pi (12.1*10^{-2})^2)sin(56.3)

\tau = 0.9422N\cdot m

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Answer:

x2 = 0.99

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Answer:

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Explanation:

Velocity Vector

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a.

The explorer wants to swim across a river to his campsite, as shown in the image below. The river has a velocity vr and the explorer can swim at ve in still water. If he swam directly to the campsite, he would end up in a point below it because the river would push him down. He must swim with a velocity such that he overcomes the stream but he advances to its objective. Let's call the angle he must swim at respect to the shoreline to achieve his goal. The explorer's velocity can be decomposed in its rectangular components vx and vy. To overcome the river's velocity:

v_{ey}=v_r

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