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marta [7]
4 years ago
6

The force of attraction that holds crystals together are called

Chemistry
1 answer:
Flauer [41]4 years ago
8 0
Intermolecular force
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In a _______ wave the matter in the medium moves back and forth at right angles to the direction
Anni [7]

Transverse.

Longitudinal travels in the same direction as medium.

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2 years ago
How many grams are in 0.00321 mol NI
Anika [276]

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

mol = mass : molar mass

mass = mol x molar mass

Molar mass = 58,6934 g/mol

Input the value :

mass = 0.0321 x 58,6934 g/mol

mass = 1.884 g

6 0
3 years ago
Which of the following is the correct model of C3H18? ​
Montano1993 [528]

Answer:

B.

General Formulas and Concepts:

<u>Chemistry - Organic</u>

  • Hydrocarbons
  • Bond-Line Notation: Each "arrow" point represents a carbon and the lines represent a bond between the carbons. Hydrogens are assumed added when drawing the molecular formulas

Explanation:

We are given C₈H₁₈. We need a Bond-Line notation where there are 8 "arrow" points (which represent Carbon). We can disregard the Hydrogens as they are assumed to take the rest of the bonds.

Only option B has a value of 8 carbons, represented by the "arrow" points. Therefore, it is the correct answer.

7 0
3 years ago
Diferences between a Human and a Lion
svp [43]
Lions walk on 4 legs, humans walk on 2. female lions live in groups but are taken over by groups of male lions from time to time, human adults tend to live alone or in pairs with their offspring. Humans can talk and lions cannot. lions have manes around the face.
4 0
3 years ago
Gaseous ethane (CH,CH,) will react with gaseous oxygen (0,) to produce gaseous carbon dioxide (CO) and gaseous water (H2O). Supp
notka56 [123]

Answer:

0.00 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.  

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.  

Mᵣ            30.07      32.00  

              2CH₃CH₃ + 7O₂ ⟶ 4CO₂ + 6H₂O

Mass/g:      1.50          11.

2. Calculate the moles of each reactant  

\text{moles of C$_{2}$H}_{6} = \text{1.50 g C$_{2}$H}_{6} \times \dfrac{\text{1 mol C$_{2}$H}_{6}}{\text{30.07 g C$_{2}$H}_{6}} = \text{0.04988 mol C$_{2}$H}_{6}\\\\\text{moles of O}_{2} = \text{11. g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.34 mol O}_{2}

3. Calculate the moles of CO₂ we can obtain from each reactant

From ethane:

The molar ratio is 4 mol CO₂:2 mol C₂H₆

\text{Moles of CO}_{2} = \text{0.04988 mol C$_{2}$H}_{6} \times \dfrac{\text{4 mol CO}_{2}}{\text{2 mol C$_{2}$H}_{6}} = \text{0.09976 mol CO}_{2}

From oxygen:

The molar ratio is 4 mol CO₂:7 mol O₂

\text{Moles of CO}_{2} =  \text{0.34 mol O}_{2}\times \dfrac{\text{4 mol CO}_{2}}{\text{7 mol O}_{2}} = \text{0.20 mol CO}_{2}

4. Identify the limiting and excess reactants

The limiting reactant is ethane, because it gives the smaller amount of CO₂.

The excess reactant is oxygen.

5. Mass of ethane left over.

Ethane is the limiting reactant. It will be completely used up.

The mass of ethane left over will be 0.00 g.

8 0
3 years ago
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