Answer:
The molar mass of the acid is 1067.42 g/mol
Explanation:
A monotropic acid can donate one proton only in a acd base reaction thus
Monotropic acid + NaOH → NaSalt + H₂O
From the above reaction, one mole of NaOH reacts with one mole of monotropc acid
however there are 0.1578 M NaOH from 15.24 mL hence we have
Number of moles of NaOH = 0.1578 M/L × (15.24/1000) L = 0.002404872 M of NaOH
The number of moles of the monotropic acid = number of moles of NaOH = 0.0024 M. However Number of moles = mass/(molar mass)
Therefore molar mass = mass/number of moles = 2.567(2.4×10⁻³) = 1067.42 g/mol
