Keq = products / reagents
N2O4(g) ⇄ 2 NO2(g)
Keq = [ NO2 ]² / [ N2O4 ]
hope this helps!
Electrons basically ARE the chemical bond. The atoms are joined together by the bonds.
<h2>Answer:</h2>
<em>Third option is correct, 7.5 grams of CuI.</em>
<h3>Explanation:</h3>
Given data :
Mass of copper = 10 grams
Mass of iodine = 10 grams
theoretical yield of copper iodide = ?
Solution:
Moles of Cu: 10 / 63.5 = 0.157 mol.
Moles of I2: 10 / 254 = 0.039 mol.
Equation : 2Cu + I2 → 2CuI
Limiting reactant : I2
So Moles of CuI produced = 0.039 mol.
Mass of CuI = 0.039 mol * 190.5 = around 7.5g
<span>n = PV / RT = 733 torr *0.961 L / 62.363 L torr K^-1 mol^-1 * 294 K = 0.038419617 mol </span>
