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2 years ago

How many carbon monoxide molecules are in 0.75 moles of carbon monoxide?

Chemistry

2 answers:

Flauer [41]2 years ago

6 0

Answer:

0.75 ( 6.02 × 10²³) = 4.515 x 10²³

Explanation:

0.75 ( 6.02 × 10²³) = 4.515 x 10²³

Hunter-Best [27]2 years ago

3 0

Answer:

four 0.5 times 10 to the 23rd Adams of Neptune

Explanation:

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The boiling point of chloroform is 61.7 C. The enthalapy of vaporization is 31.4 kj/mol. Caculate the entropy of vaporization. D

dedylja [7]

Answer:

Δ S = 93.8 J/mol-K

Explanation:

Given,

Boiling point of chloroform = 61.7 °C

= 273 + 61.7 = 334.7 K.

Enthalapy of vapourization = 31.4 kJ/mol.

Using Gibbs free energy equation

Δ G = Δ H - T (ΔS)

at equilibrium (when the liquid is boiling), Δ G = 0

so, 0 = ΔH - T (Δ S)

T (Δ S) = Δ H

and ΔS = ΔH / T

Δ S = (31400 J/mol.) / 334.7 K

Δ S = 93.8 J/mol-K

6 0

3 years ago

Which statements correctly describe the rock cycle? Check all that apply.

pickupchik [31]

Answer: I italicize for checking

Rocks are preserved through the process.
Rocks change from one type to another.
Different rock groups are interrelated.
Rocks change from one type to another in a specific order.
Environmental conditions influence a change in rock type.

Explanation:

Rocks are preserved, as in you can't destroy them completely, but no, they don't stay the same they change.

3 0

3 years ago

The lower the ph of a solution, the ______.

gtnhenbr [62]

B

a and c are unrelated
d: ph will increase

3 0

4 years ago

Read 2 more answers

which person possessed the expeirence and to be commander in chief and continental army, in John Adams opinion?

sasho [114]

George Washington is your answer

Hope this helps!

6 0

3 years ago

c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ

Umnica [9.8K]

Answer: 72 grams of water will be produced.

Explanation:

To calculate the number of moles, we use the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

$\text{moles of propane}=\frac{44g}{44g/mol}=1mole$

For the reaction of combustion reaction of propane, the equation follows:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = $\frac{1}{1}\times 4=4moles$ of water.

Now, to calculate the amount of water, we use equation 1, we get:

Molar mass of water = 18 g/mol

$4mol=\frac{\text{Mass of water}}{18g/mol}$

Mass of water produced = 72 grams

Hence, 72 grams of water will be produced.

6 0

3 years ago