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Vitek1552 [10]
2 years ago
10

Diferences between a Human and a Lion

Chemistry
1 answer:
svp [43]2 years ago
4 0
Lions walk on 4 legs, humans walk on 2. female lions live in groups but are taken over by groups of male lions from time to time, human adults tend to live alone or in pairs with their offspring. Humans can talk and lions cannot. lions have manes around the face.
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What are the difference between a red giant and a red super giant
bixtya [17]

So, unlike red giants, red supergiants are simply bright, red stars. It so happens that they may be in the same evolutionary state, but it is also possible that they have moved on. For example, most massive stars will appear as red supergiants while helium is fused into carbon in the core.



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8 0
3 years ago
Read 2 more answers
Wine has a pH of 3, which means it is __________ times more acidic than tomatoes, which have a pH of 4.
Natasha2012 [34]

Answer:

10

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

Thus, from the formula, more the concentration of the hydrogen ions or more the acidic the solution is, the less is the pH value of the solution.

Thus, solution with pH = 3 will be more acidic than solution with pH =4  

Thus, concentration of the [H⁺] when pH =3

3 = - log [H⁺]

[H⁺] = 10⁻³ M

For pH = 4, [H⁺] = 10⁻⁴ M

<u>hence, pH = 3 is 10 times more acidic than pH = 4</u>

5 0
3 years ago
Why is NaNO3 a homogenous mixture in terms of particle arrangement/composition?
Fed [463]
<span> A homogeneous mixture is composed of a single visible phase while a heterogeneous mixture has two or more</span>
8 0
3 years ago
Hermit crabs and anemones have a mutualistic relationship. Which of these statements best describes how they interact?
liubo4ka [24]

Answer:  anemones cannot move very quickly, but they can sting predators. When an anemone is riding on a hermit crab's shell, the anemone protects the crab from predators.

Explanation:

5 0
2 years ago
Given that Δ H ∘ f [ Br ( g ) ] = 111.9 kJ ⋅ mol − 1 Δ H ∘ f [ C ( g ) ] = 716.7 kJ ⋅ mol − 1 Δ H ∘ f [ CBr 4 ( g ) ] = 29.4 kJ
JulsSmile [24]

Answer:

283.725 kJ ⋅ mol − 1

Explanation:

C(s) + 2Br2(g) ⇒ CBr4(g) , Δ H ∘ = 29.4 kJ ⋅ mol − 1

\frac{1}{2}Br2(g) ⇒ Br(g) ,  Δ H ∘ = 111.9 kJ ⋅ mol − 1

C(s) ⇒ C(g) ,  Δ H ∘ = 716.7 kJ ⋅ mol − 1

4*eqn(2) + eqn(3) ⇒ 2Br2(g) + C(s) ⇒ 4 Br(g) + C(g) , Δ H ∘ = 1164.3 kJ ⋅ mol − 1

eqn(1) - eqn(4) ⇒ 4 Br(g) + C(g) ⇒ CBr4(g) , Δ H ∘ = -1134.9 kJ ⋅ mol − 1

so,

   average bond enthalpy is \frac{1134.9}{4} = 283.725 kJ ⋅ mol − 1

4 0
3 years ago
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