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irinina [24]
3 years ago
10

As part of a science experiment, Jose did a test for starch on a slice of apple and a slice of potato. The yellow-orange iodine

solution stayed the same color when it was put on the apple, but it became black on the potato. Why did the iodine solution change color on the potato? A. The iodine evaporated into a gas. B. The iodine mixed with the colors of the potato so it looked black. C. The iodine burned the potato and turned it to ash. D. The iodine reacted with the potato to form a new substance.
Chemistry
1 answer:
rosijanka [135]3 years ago
4 0
I am pretty sure the answer is D
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2 years ago
If the heat of reaction is negative, that means that:
Crazy boy [7]

Answer:

if the heat of reaction is positive, the reaction is said to be endothermic; if negative, exothermic.

Explanation:

hope this helps

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4 0
2 years ago
If the visible light spectrum is from 400 to 700 nm, would light with an energy of 2.79 x 10^-19 J be visible with the naked eye
sladkih [1.3K]

Answer:

713 nm. It is not visible with the naked eye.

Explanation:

Step 1: Given data

  • Energy of light (E): 2.79 × 10⁻¹⁹ J
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s
  • Speed of light (c): 3.00 × 10⁸ m/s
  • Wavelength (λ): ?

Step 2: Calculate the wavelength of the light

We will use the Planck-Einstein equation.

E = h × c / λ

λ = h × c / E

λ = 6.63 × 10⁻³⁴ J.s × 3.00 × 10⁸ m/s / 2.79 × 10⁻¹⁹ J

λ = 7.13 × 10⁻⁷ m

Step 3: Convert "λ" to nm

We will use the relationship 1 m = 10⁹ nm.

7.13 × 10⁻⁷ m × (10⁹ nm/1 m) = 713 nm

This light is not in the 400-700 nm interval so it is not visible with the naked eye.

5 0
3 years ago
How much energy will it take to raise the temperature of 75.0 g of water from 20.0°C to 55.0°C?
Hatshy [7]

Answer:

We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the water is 55°C and the initial temperature is 20.0°C, ΔT is as follows:

ΔT = Tfinal − Tinitial = 55.0°C − 20.0°C = 35.0°C

given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:

=  heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =

= 75x1x35=2625 cal

6 0
3 years ago
Please help me with this chemistry question
aliina [53]

Answer:

A.

Explanation:

8 0
3 years ago
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