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Rasek [7]
3 years ago
9

Can someone answer this pls

Chemistry
1 answer:
sineoko [7]3 years ago
5 0

Answer:12

Explanation:

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What is the number of atoms in 3.75 mol fe
Kruka [31]
1mol=6.022x10^23 atoms
3.75mol= 6.022x3.75x10^23 atoms
             =2.2583x10^24 atoms
8 0
3 years ago
The pipet used for transferring the pickle juice to the flask was dirty and consequentially some of the pickle juice stuck to th
lesya [120]

Explanation:

Since, some of the given sample is stuck inside and behind the pipet. Hence, there will occur a decrease in the percent of acetic acid.

This is because a decrease in concentration of the acid will also lead to a decrease in the amount of sample taken for the estimation. Since. lesser is the amount or concentration present lesser will be its analyte concentration.

For example, we took 10 mg of a pickel sample but 3 mg of the sample remain stuck in the pipet. This means we actually titrating a  sample less than 10 mg.

Therefore, the analyte concentration in the pickel will also be less.

6 0
4 years ago
Two objects are brought into contact Object 1 has mass 0.76 kg, specific heat capacity 0.87) g'c and initial temperature 52.2 'C
taurus [48]

Answer:

T_F=77.4\°C

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

Q_1=-Q_2

In terms of mass, specific heat and temperature change is:

m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)

Now, solve for the final temperature, as follows:

T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}

Then, plug in the masses, specific heat and temperatures to obtain:

T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

4 0
3 years ago
How to solve 2 and 3
GarryVolchara [31]
Use the Heat formula for both problems.

q=m*c*∆t

Where
q= heat in Joules
m= mass in grams
c= specific heat which is a constant 4.18
∆t= change in temperature
3 0
3 years ago
What are the final materials of a reaction called? Where are they located in an<br> equation?
fredd [130]

Answer:

Reactants are starting materials and are written on the left-hand side of the equation. Products are the end-result of the reaction and are written on the right-hand side of the equation.

Explanation:

4 0
3 years ago
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