Answer:
Dimer of two peptide chains with 1 mole of molybdenum metal each.
Explanation:
Percentage of molybdenum in protein = 0.08%
Molecular mass of nitrate reductase = 240,000 g
Mass of molybdenum = x
Moles of molybdenum =
Each peptide chain of nitrate reductase contain 1 mole of molybdenum.
This means that nitrate reductase is composed of to two peptide chains. And in each peptide there is a single mole of molybdenum metal.
Answer:
<em> = 0.2 mL.</em>
Explanation:
Given a 0.5 M solution of NaOH as stock solution, 10.0mL of 0.010M can be prepared via dilution with distilled water, by using the formula:
where C1 and V1 are initial concentration and volume respectively; same as C2 & V2 for fina.
Let C1 = 0.5M, V2 = ?
C2 = 0.010M; V2 = 10mL
⇒Volume of stock solution to be diluted, V2
= × 0.010
<em> = 0.2 mL.</em>
Glasswares used would be pipette (for smaller volume experiment) and measuring cylinder. 0.2mL would be measured and then made upto the 10mL mark of the measuring cylinder.
I hope this was a detailed explanation given the missing details of "Trial 1" in the question.