Peter's account is 910-40x, and Marla's account is 470-2x. This is a system, so you must find the number that makes both equations end up with the same number. Basically trial and error. Here is what I did:
Let's try the number 10. 910-400=510 and 470-20=450. I need a higher number.
Let's try 13 next. 910-520=390 and 470-26=444. Now the number has to be lower.
Let's try 12. 910-480=430 and 470-24=446. Close, and a little lower.
11.5 is too low, and 11.7 is too high. 11.6 has Equation 1 at 446 and Equation 2 at 446.8. Very close!
It is somewhere around 11.6. I hope that this can give you a start in figuring it out, because I don't believe in giving the complete answer, because then you do not learn anything from it.
The volume of a sphere, V = (4/3)(PI)(R^3)
Let k = (4/3)(PI)
Therefore, V = k (R^3)
Let R’ = new radius = 2R
V’ =k (R’^3)
= k (2R)^3
= 8 k R^3
= 8 V
The volume would be eight time the original volume.
graph of g is the the graph of f shifted 3 units above
i dont know if the translator translate that coreclty
Answer:
B = 
*r^2
(Base of the cone)
Step-by-step explanation:
The volume of the cone is always 1/3 of the volume of a cylinder with the same radius and height.
Volume of the cylinder
V_cylin = ( *r^2 )* h
Where
r is the radius
h is the height
This means the volume of the cone is equal to
V_cone = (1/3)* ( *r^2 )* h
By looking to the equation of the problem
V=(1/3)Bh
We can easily deduce that
B = *r^2
(Base of the cone)
Answer:
The ratio of planet B's volume to planet A's volume is 1:512 or 1/512
Step-by-step explanation:
Volume of sphere = 4/3 π r^3
r = d/2
Radius of palnet A = 8/2 = 4
Radius of planet B = 1/2
Since 4/3 π is same in both volumes so, they cancel out when finding ratio.
Now ratio depends on radius cube of both planets
Volume of Planet B : Volume of Planet A
4/3 π(1/2)^3 : 4/3 π(4)^3
Cancelling 4/3 π on both sides
1/8 : 64
Multiply 8 on both sides
1 : 512
So, The ratio of planet B's volume to planet A's volume is 1:512 or 1/512
