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uranmaximum [27]
3 years ago
9

Which step will decrease the pressure of a gas inside a closed cubical container?

Chemistry
2 answers:
Cloud [144]3 years ago
8 0
Lowering temperature decreases pressure, and gaining volume also decreases pressure
notka56 [123]3 years ago
3 0
Strep 3 xmxxkdkdkkskdkkckckcmfmcmcmcmcm
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A can of coke contains 25 mL of carbon dioxide gas at 100kPa. If you take it on a hike up Mount Everest and the pressure decreas
Mazyrski [523]

Answer:

50 mL

Explanation:

We can solve this problem by using Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

p\propto \frac{1}{V}

where

p is the pressure of the gas

V is the volume of the gas

The equation can be rewritten as

p_1 V_1 = p_2 V_2

where in this problem:

p_1 = 100 kPa is the initial pressure of the gas in the coke

V_1=25 mL is the initial volume

p_2=50 kPa is the final pressure

Solving for V2, we find the final volume:

V_2=\frac{p_1 V_1}{p_2}=\frac{(100)(25)}{50}=50 mL

7 0
4 years ago
to balance a chemical equation, only the subscript of reactant and product can be changed. true or false
Lostsunrise [7]

Answer:

False

Explanation:

:)

6 0
3 years ago
If there are two similar,oxygen -containing ions, the ion with more oxygen atoms ends in
Taya2010 [7]
The answer is  -ate:

If there are two similar, oxygen-containing ions, the ion with more oxygen atoms ends in -ate.     
5 0
3 years ago
Read 2 more answers
How many grams of Br2 are needed to completely convert 15.0 g Al to AlBr3 ?
wariber [46]

Answer:

133 g

Explanation:

Step 1: Write the balanced equation

2 Al(s) + 3 Br₂(l) ⇒ 2 AlBr₃(s)

Step 2: Calculate the moles corresponding to 15.0 g of Al

The molar mass of aluminum is 26.98 g/mol. The moles corresponding to 15.0 g of Al are:

15.0g \times \frac{1mol}{26.98g} = 0.556mol

Step 3: Calculate the moles of Br₂ that react with 0.556 moles of Al

The molar ratio of Al to Br₂ is 2:3. The moles of bromine that react with 0.556 moles of aluminum are:

0.556molAl \times \frac{3molBr_2}{2molAl} = 0.834molBr_2

Step 4: Calculate the mass corresponding to 0.834 moles of Br₂

The molar mass of bromine is 159.81 g/mol. The mass corresponding to 0.834 moles of Br₂ is:

0.834mol \times \frac{159.81g}{mol} = 133 g

8 0
3 years ago
PLEASE HELP
astraxan [27]

Answer:student 3

Explanation:

5 0
3 years ago
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