Answer:
<h2>The answer is option A</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of object = 7 cm³
density = 5 g/cm³
The mass of the object is
mass = 5 × 7
We have the final answer as
<h2>35 g</h2>
Hope this helps you
Answer:
Sorry I am not very good at chemistry.
Explanation:
Explanation:
A solution is said to saturated when it cannot dissolve any extra solute in it. The extra solute put remains undissolved.
A solution is said to unsaturated, when the concentration of solute is less as compared to solubility of the solution it is said to be unsaturated.
A solution is said to be super saturated when it contains more of the solute than the solvent can dissolve under normal conditions is called super saturated.
Answer:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.03901 mol/liter
- [Cl₂O] = 0.02351 mol/liter
Explanation:
<u />
<u>1. Chemical reaction:</u>
<u>2. Initial concentrations:</u>
i) 1.3 g H₂O
- Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol
- Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter
ii) 2.2 g Cl₂O
- Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol
- Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter
<u>3. ICE (Initial, Change, Equilibrium) table</u>
I 0.0481 0.0326 0
C -x -x +x
E 0.0481-x 0.0326-x x
<u />
<u>4. Equilibrium expression</u>
![K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}](https://tex.z-dn.net/?f=K_c%3D%5Cdfrac%7B%5BHOCl%5D%5E2%7D%7B%5BH_2O%5D.%5BCl_2O%5D%7D)
<u />
<u>5. Solve:</u>
Use the quadatic formula:
The positive result is x = 0.00909
Thus the concentrations are:
- [HOCl] = 0.00909 mol/liter
- [H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter
- [Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter
1) All the CO2 comes from the C24 H30 N3 O
2) To balance C from CO2 with C from C24, the ratio of cC24 H30 N3 O to CO2 is 24 / 1
3) Convert 1.20 g of CO2 to number of moles
number of moles = mass in grams / molar mass
mass = 1.20 g
molar mass = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol
number of moles = 1.2 g / 44.01 g/mol = 0.0273 mol
4) proportion
1 mol C24 H30 N3 O / 24 mol CO2 = x / 0.0273 mol CO2
=> x = 0.0273 mol CO2 * 1 mol C24H30N3O / 24 mol CO2 = 0.00114 mol C24H30N3O
5) Convert 0.00114 mol C24H30N3O to grams
molar mass = 376.5 g/mol
mass = 0.00114 mol * 376.5 g/mol = 0.429 g
6) mass percent in the mixture
mass percent = (mass of lsd / mass of mixture) * 100 = (0.429g / 1.0g) * 100 = 42.9%
Answer: 42.9%
