Wave y and wave z are two types of electromagnetic waves traveling through a vacuum suppose the frequency of wave y is about thr
2 answers:
Answer: The energy of wave-y will more than the energy of wave-z. Since,frequency of wave-z is less than the frequency of wave-y
Explanation:
Let the frequency of the wave z be
Given that frequency of wave y is about three times greater than the frequency of wave-z.
Then frequency of wave-y :
Frequency of wave-z is less than the frequency of wave-y:
The energy of the electromagnetic waves with frequency is given by:
, h= Planck's constant
Energy of the wave is directly proportional to the frequency of the wave.
The energy of wave-y will be more than the energy of wave-z. Since,frequency of wave-z is less than the frequency of wave-y
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The molar concentration of the original HF solution : 0.342 M
Further explanation
Given
31.2 ml of 0.200 M NaOH
18.2 ml of HF
Required
The molar concentration of HF
Solution
Titration formula
M₁V₁n₁=M₂V₂n₂
n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)
Titrant = NaOH(1)
Titrate = HF(2)
Input the value :