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3 years ago

Find the distance between (5 , 1 ) and ( 3 ,6)

Mathematics

1 answer:

crimeas [40]3 years ago

5 0

Answer:

Step-by-step explanation:

$\sqrt{(6-1)^{2}+(3-5)^{2} }$ = $\sqrt{29}$

=5.39(correct to nearest hundredth)

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How to do this question plz

hjlf

Answer:

$\underline{ \boxed{ \underline{part \: a}}}. \\the \: required \: distance \: a part \: be \to \: \boxed{\underline {\overline{p } =79.23 \: km} } \\ \\ \underline{ \boxed{ \underline{part \: b}}}. \\ the \: bearing \: of \: \boxed{ B } \: \: from \: \boxed{ \underline{A}} \: is \to \boxed{ \underline{324 }\degree }$

Step-by-step explanation:

$\underline{ \boxed{ \underline{part \: a}}}. \\ l et \: the \: required \: distance \: apart \: be \to \: \boxed{ \overline {p}} \\ let \: \boxed{ \angle \: P} \: be \: the \: angle \: of \: seperation \: between \: both \: ships :given \: by \to \\ P = (244 - 180) - (196 - 180 )= (64 -16) = \boxed{48 \degree} \\ if \: ship \: A \: and \: B \: left \: the \: port\: at \: (10:30) \: \\ then \: at \: (14 :00) \: their \: time \: interval \: would \: be \to \\ (14 : 00) - (10 : 30) = \boxed{ 3.5 \: hrs} \\ ship \: \boxed{A }\: distance \: from \: the \: port =( v \times t) = (30 \times 3.5) = \boxed{105 \: km} \\ ship \: \boxed{B }\: distance \: from \: the \: port =( v \times t) = (24 \times 3.5) = \boxed{84\: km} \\n ow........we \: cant \: do \: much \: if \: their \: are \: no \: angles \: to \: work \: with \to \\ applying \:t he \: cosine \: rule : we \: have \to \\ \cos(P) = \frac{ {a}^{2} + {b}^{2} - \overline{{p}^{2} } }{2(ab)} \\ {a}^{2} + {b}^{2} - \overline{{p}^{2} } = 2(ab) \cos(P) \\ \overline{{p}^{2} } = {a}^{2} + {b}^{2} - \{2(ab) \cos(P) \} \\ \overline{{p}^{2} } = {84}^{2} + {105}^{2} - \{2(84)(105) \cos(48 \degree) \} \\\overline{{p}^{2} } = 18,081 - 11,803.463897 \\ \overline{{p}^{2} } = 6,277.536103 \\ \overline{p } = \sqrt{6,277.536103} \\ \boxed{\underline {\overline{p } =79.23 \: km} } \\ \\ \underline{ \boxed{ \underline{part \: b}}}. \\ to \: sove \: this : we \: first \: find \: angle \: \angle \: B : by \: applying \to \\ \frac{ \sin(B) }{b} = \frac{ \sin(P) }{p} \\ p \ast \sin(B) = b \ast \sin(P) \\ B = \sin {}^{ - 1} ( \frac{ b \ast \sin(P)}{p} ) \\ B = \sin {}^{ - 1} ( \frac{ 105 \times \sin(48 \degree)}{79.230903712} ) \\ \\ B = \sin {}^{ - 1} ( \frac{ 78.030206678}{79.230903712} ) \\ \\ B = \sin {}^{ - 1} (0.9848455971) \\ \boxed{B = 80 \degree} \\ hence \ : the \: bearing \: of \: \boxed{ B } \: \: from \: \boxed{ \underline{A}} \: is \to \\ 360 - \{180 - (80 + 48 + 16) \} \\ 360 -(180 - 144 )\\ 360 -36 = \boxed{324 \degree }$

♨Rage♨

7 0

3 years ago

Solve using Elimination<br><br> 3x+y=-9<br> y=5x+7

valentinak56 [21]

Answer

x=-2 and y=-3

Step-by-step explanation:

Step: Solvey=5x+7for y:

Step: Substitute5x+7 for y in 3x+y=−9:

3x+y=−9

3x+5x+7=−9

8x+7=−9(Simplify both sides of the equation)

8x+7+−7=−9+−7(Add -7 to both sides)

8x=−16

8x/8=−16/8

(Divide both sides by 8)

x=−2

Step: Substitute−2 for x in y=5x+7:

y=5x+7

y=(5)(−2)+7

y=−3(Simplify both sides of the equation)

7 0

3 years ago

What is the slope intercept form of y= -2

Mashcka [7]

The slope-intercept form: y = mx + b

(m - slope, b - y-intercept)

We have y = -2. It's the slope intercept form where m = 0 and b = -2.

y = -2 → y = 0x - 2

8 0

3 years ago

Andrew is riding his bike. He biked a distance of 14 miles at a rate of 7 miles per hour. Using the distance formula, d = rt, so

rusak2 [61]

The computation shows that the time taken is 120 minutes.

<h3>How to illustrate the information?</h3>

From the information, Andrew is riding his bike and he biked a distance of 14 miles at a rate of 7 miles per hour.

Therefore, time taken for 14 miles will be:

= 14/7

= 2 hours

= 2 × 60 = 120 minutes

The time taken is 120 minutes.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

3 0

2 years ago

When i have a negative plus a positive of the same number , what is that called ?

Lady bird [3.3K]

Answer: Integer

Step-by-step explanation: The answer would be integer

3 0

3 years ago