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jeka57 [31]
3 years ago
11

For c2h3o2−, write an equation that shows how the anion acts as a base.

Chemistry
2 answers:
velikii [3]3 years ago
4 0
The synthetic compound Zn(C2H3O2)2 is zinc acetic acid derivation. The molecular composition demonstrates that the mixes incorporate zinc, spoke to by Zn; carbon, spoke to by C; hydrogen, spoke to by H; and oxygen, spoke to by O. Below is the <span>an equation that shows how the anion acts as a base:

</span>

C2H3O2−(aq)+H2O(l)⇌<span>HC2H3O2(aq)+OH−(aq)</span>

Ray Of Light [21]3 years ago
3 0

Explanations:- Acetate ion is a conjugate base of a weak acid(acetic acid). From Bronsted-Lowry concept of acid and base, "Acids are proton donor where as bases are proton acceptors.

To work as a base, acetate ion would be accepting a proton. Water is an amphoteric compound means it could act as an acid as well as a base. So, let's write the reaction of acetate ion with water to show how it acts as a base.

C_2H_3O_2^-(aq)+H_2O(l)\rightleftharpoons HC_2H_3O_2(aq)+OH^-(aq)

In the above reaction, acetate ion has accepted a proton from water means its a base and since water has donated a proton so its an acid.

Acetic acid is the conjugate acid of acetate ion and hydroxide ion is the conjugate base of water.

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The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc
jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2HBr(g)\rightarrow H_2(g)+Br_2(g

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}

Given: -\frac{d[HBr]}{dt}]=0.301

Putting in the values we get:

\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}

+\frac{1d[Br_2]}{dt}=0.151

Thus the rate of appearance of Br_2 is 0.151

8 0
3 years ago
At what point on the hill will the car have zero gravitational potential energy? A) Half-way down the hill. B) At the top of the
kompoz [17]

I think it’s c cause height is what determines gravitational potential energy

3 0
3 years ago
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The law of conservation of mass states that mass is neither created nor destroyed during a chemical reaction. This can be gleane
GenaCL600 [577]

Answer : The total mass of oxygen gas released in the reaction will be, 12.8 grams

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2MgO\rightarrow 2Mg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2MgO = Total mass of 2Mg+O_2

or,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

As we are given :

Total mass of MgO = 16.12 grams

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So,

Total mass of 2MgO = Mass of 2Mg  + Mass of O_2

2\times 16.12g=2\times 9.72g+\text{Mass of }O_2

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8 0
3 years ago
Which step will decrease the pressure of a gas inside a closed cubical container
Dmitry_Shevchenko [17]
In order to <span>decrease the pressure of a gas inside a closed cubical container, you need to decrease the temperature of the container. The volume of the system is rigid so it means volume is constant. By the ideal gas law, temperature and pressure are directly related. Increasing the temperature, increases the pressure and the opposite to happens.</span>
6 0
3 years ago
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Why is conical flask used in the freezing point of naphthalene activity?
SpyIntel [72]

Answer:

D. To ensure the cooling process is not affected by surrounding temperature

Explanation:

The conical flask acts as a <u>t</u><u>e</u><u>m</u><u>p</u><u>e</u><u>r</u><u>a</u><u>t</u><u>u</u><u>r</u><u>e</u><u> </u><u>j</u><u>a</u><u>c</u><u>k</u><u>e</u><u>t</u><u>.</u>

6 0
3 years ago
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