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kaheart [24]
3 years ago
6

Can somebody help please real quick

Mathematics
2 answers:
mylen [45]3 years ago
8 0

I think it's the 2nd option.

MaRussiya [10]3 years ago
6 0

It should be the second one

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Three consecutive even numbers add up to 36. Select all of the following equations that will find the lowest number of the three
Misha Larkins [42]

Equation A find the lowest number of the three. Equation A satisfies the given conditions.

<h3>What is even number? </h3>

If the number is divisible by 2 then the number will be an even number. Similarly, the number is not divisible by 2 then the number will be an odd number.

Assume the three consecutive integers are 2x,2x+2,2x+4

The sum of the three consecutive even numbers are 36;

x+x+2+x+4 = 36

3x+6=36

3x=30

x=10

The three integers are found as;

x =10

x+2 = 10+2 = 12

2x+4 =10+4=14

Hence, equation A find the lowest number of the three. Equation A satisfies the given conditions.

To learn more about the even number, refer to the link;

brainly.com/question/2289438

#SPJ1

5 0
2 years ago
the cost of old boiler is £775 per year,the new one is £1850 ,the cost of using a new boiler will be 1/5 less than the cost of u
Tanya [424]

Answer:

I think its 12.3 years

Step-by-step explanation:

a fifth of 775 is 155 and 155 x 12.3 = 1850

4 0
3 years ago
5 ft 9 ft<br> gft/ 7H-<br> 2 ft<br> 13 ft<br> Surface Area:<br> Volume:
Jet001 [13]

Answer:           you like it if I could double the height of your cat food can?” 6 in. 7 in. 15 cm. 30 cm. 13 ft. 6 ft ... 3 ft. 2 ft. 4 ft. 2. 5 m. 8 m. 8 m. Areas of bases. Areas of lateral faces. Exercises 7–9. Lesson Tutorials ... WRAPPING PAPER A cube-shaped gift is.

8 0
3 years ago
Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
Nataly_w [17]

Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

coefficient of x^{2} in the expansion of (2+x - x^{2})^{6} = (240 - 192) = 48

Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

for k = 5, the coefficient of  x^{2}  is , (-32) \times 6 = -192

for k = 6 , the coefficient of x^{2} is, 6_{C_{2}} \times 2^{4} = 240

so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

3 0
3 years ago
A lottery has 60 numbers. To win the jackpot one needs to match all 7 numbers that are drawn by the machine. Is this a PERMUTATI
Vadim26 [7]

Answer: Hence, our required probability is \dfrac{1}{386206920}

Step-by-step explanation:

Since we have given that

Numbers in a lottery = 60

Numbers to win the jackpot = 7 numbers

We need to find the probability to hit the jackpot:

So, our required probability is given by

P=\dfrac{^7C_7}{^{60}C_7}\\\\P=\dfrac{1}{386206920}

This is a combination problem as we need to select 7 numbers irrespective of any arrangements.

Hence, our required probability is [tex]\dfrac{1}{386206920}[/tex

4 0
3 years ago
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