Question

A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripetal force on the bicyclist?

Answer 1

Hello!

A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripetal force on the bicyclist ?

We have the following data:

Centripetal Force = ? (Newton)

m (mass) = 112 Kg

s (speed) = 8.9 m/s

R (radius) = 15.5 m  

Formula:

$\boxed{F_{centripetal\:force} = \dfrac{m*s^2}{R}}$

Solving:

$F_{centripetal\:force} = \dfrac{m*s^2}{R}$

$F_{centripetal\:force} = \dfrac{112*8.9^2}{15.5}$

$F_{centripetal\:force} = \dfrac{112*79.21}{15.5}$

$F_{centripetal\:force} = \dfrac{8871.52}{15.5}$

$F_{centripetal\:force} = 572.356129...$

$\boxed{\boxed{F_{centripetal\:force} \approx 572.36\:N}}\end{array}}\qquad\checkmark$

Answer:

The centripetal force on the bicyclist is approximately 572.36 N

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I Hope this helps, greetings ... Dexteright02! =)

Answer 2

The centripetal force, Fc, is calculated through the equation, 
                                    Fc = mv²/r
where m is the mass,v is the velocity, and r is the radius. 
Substituting the known values,
                                     Fc = (112 kg)(8.9 m/s)² / (15.5 m)
                                         = 572.36 N
Therefore, the centripetal force of the bicyclist is approximately 572.36 N.