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shepuryov [24]
3 years ago
5

A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripet

al force on the bicyclist?
Physics
2 answers:
Goryan [66]3 years ago
5 0

Hello!

A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripetal force on the bicyclist ?

We have the following data:

Centripetal Force = ? (Newton)

m (mass) = 112 Kg

s (speed) = 8.9 m/s

R (radius) = 15.5 m  

Formula:

\boxed{F_{centripetal\:force} = \dfrac{m*s^2}{R}}

Solving:

F_{centripetal\:force} = \dfrac{m*s^2}{R}

F_{centripetal\:force} = \dfrac{112*8.9^2}{15.5}

F_{centripetal\:force} = \dfrac{112*79.21}{15.5}

F_{centripetal\:force} = \dfrac{8871.52}{15.5}

F_{centripetal\:force} = 572.356129...

\boxed{\boxed{F_{centripetal\:force} \approx 572.36\:N}}\end{array}}\qquad\checkmark

Answer:

The centripetal force on the bicyclist is approximately 572.36 N

____________________________________

I Hope this helps, greetings ... Dexteright02! =)

kogti [31]3 years ago
4 0
The centripetal force, Fc, is calculated through the equation, 
                                    Fc = mv²/r
where m is the mass,v is the velocity, and r is the radius. 
Substituting the known values,
                                     Fc = (112 kg)(8.9 m/s)² / (15.5 m)
                                         = 572.36 N
Therefore, the centripetal force of the bicyclist is approximately 572.36 N. 
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d = vt = \omega r\times  t= ( \frac{64 \ rev}{\min} \times \frac{2 \pi \ rad}{rev} \times \frac{1 \min}{60 \ s} \times 0.9 \ m) \times 28 \ s\\\\d = 168.89 \ m

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