The force exerted by a magnetic field of intensity B on a wire of length L is:
![F=ILB \sin \theta](https://tex.z-dn.net/?f=F%3DILB%20%5Csin%20%5Ctheta)
where I is the current in the wire and
![\theta](https://tex.z-dn.net/?f=%5Ctheta)
is the angle between the wire and the direction of B.
In our problem, the length of the wire is L=260 m, the current is I=115 A, the intensity of the Earth's magnetic field is
![B=5.0 \cdot 10^{-5}T](https://tex.z-dn.net/?f=B%3D5.0%20%5Ccdot%2010%5E%7B-5%7DT)
and the angle between the wire and B is
![80^{\circ}](https://tex.z-dn.net/?f=80%5E%7B%5Ccirc%7D)
, and by substituting these numbers in the previous expression we can find the magnitude of the force:
B) The respiratory system would fail, and then the entire organism would suffer.
Answer : The time taken for a 50 µF capacitor to fully charge if it is in a series circuit with a 100 KΩ resistor is, 0.5 seconds.
Explanation :
RC time constant is the time constant (in seconds). It is equal to the product of the circuit resistance (in ohms) and the circuit capacitance (in farads).
The formula will be:
![\tau=R\times C](https://tex.z-dn.net/?f=%5Ctau%3DR%5Ctimes%20C)
where,
= time constant = ?
R = resistance = 100 KΩ = 100000 Ω
Conversion used : (1 KΩ = 1000 Ω)
C = capacitance = 50 μF = 50 × 10⁻⁶ F
Conversion used : (1 μF = 10⁻⁶ F)
Now put all the given values in the above formula, we get:
![\tau=(100000\Omega)\times (50\times 10^{-6}F)](https://tex.z-dn.net/?f=%5Ctau%3D%28100000%5COmega%29%5Ctimes%20%2850%5Ctimes%2010%5E%7B-6%7DF%29)
![\tau=0.5s](https://tex.z-dn.net/?f=%5Ctau%3D0.5s)
Thus, the time taken for a 50 µF capacitor to fully charge if it is in a series circuit with a 100 KΩ resistor is, 0.5 seconds.
Hello there. ^•^
<span>HOW MANY MINUTES IN A YEAR?
Answer:
525600
</span>