By definition of average acceleration,
<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²
Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:
∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N
If you just want the magnitude, drop the negative sign.
Finding acceleration= final velocity-initial velocity/ time taken (or A= V-U/T)
Final speed= 2m
Initial speed= 0m
Time taken= 2 seconds
2-0/2 so it’ll be 1m/s
2-0=0
2/2=
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Answer:
The net force acting on the car is
3
×
10
3
Newtons.
Hope this helps you
Explanation:
Force is defined as the product of the mass of the body and its aaceleration,
⇒
F
=
m
a
Substituting the above given values we get,
F
=
(
1500
k
g
)
(
2.0
m
/
s
2
)
=
3000
N
=
3
×
10
3
N
.
