Answer:
a)
a = 1/5
b = 1/3
b)
x(1/3) = 2.500
y(1/3) = 2.598
c)
x'(t) = -5π sin(π t)
d)
x'(1/3) = -13.603
Explanation:
Hi!
a)
We can notice that
x(t)/5 = cos(πt)
y(t)/3 = sin(πt)
Therefore:
( x(t) / 5 )^2 + ( y(t) / 3 )^2 = cos^2(πt) + sin^2(πt) = 1
That is:
a = 1/5
b = 1/3
b)
At t=1/3
x(1/3) = 5 cos(π/3)
y(1/3) = 3 sin(π/3)
But
cos(π/3) = 1/2 = 0.5
sin(π/3) = √3 / 2 = 0.866
That is:
x(1/3) = 2.5
y(1/3) = 2.598
c)
The horizontal velocity is:
x'(t) = -5π sin(π t)
d)
at time t =1/3
x'(1/3) = -5π sin(π/3) = -13.603
Explanation:
The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end. The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.
Sum the torques about the wedge (it may help to draw a diagram first). Take counterclockwise to be positive.
∑τ = Iα
W (0.25 m) − (100 N) (0.50 m) = 0
W = 200 N
Sum the forces in the y direction.
∑F = ma
F − 100 N − 200 N = 0
F = 300 N
Answer:
F = K Q1 Q2 / R^2 force between 2 charged partices
F2 / F1 = (R1 / R2)^2 = (1 / 2.69)^2 = .139
F2 = .139 F1
Answer:
Negative sign shows that velocity of the car is decreases at a constant rate
Explanation:
We have given velocity of the car is decreases from 32 m /sec to 24 m/sec in 4 second
So initial velocity of the car u = 32 m /sec
And finally car reaches to a velocity of 24 m/sec
Time taken to change in velocity = 4 sec
So final velocity v = 24 m/sec
From first equation of motion v = u+at
So 
Negative sign shows that velocity of the car is decreases at a constant rate
Is recommend attaching the answer choices; Meters, Liters, Grams are three basic ones
