B. If all plants are watered at least once a day then they will all grow at least 1 cm a day.
All plants grow at different rates.
Hope this helps! XD
Answer:
3.78 m on the left side of the seesaw
Explanation:
The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:
(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r
Solve for r, and you get 3.78 on the left side.
Hope this helps!
Answer:
M₂ = M then L₂ = L
M₂> M then L₂ = \frac{M}{M_{2}} L
Explanation:
This is a static equilibrium exercise, to solve it we must fix a reference system at the turning point, generally in the center of the rod. By convention counterclockwise turns are considered positive
∑ τ = 0
The mass of the rock is M and placed at a distance, L the mass of the rod M₁, is considered to be placed in its center of mass, which by uniform e is in its geometric center (x = 0) and the triangular mass M₂, with a distance L₂
The triangular shape of the second object determines that its mass can be considered concentrated in its geometric center (median) that tapers with a vertical line if the triangle is equilateral, the most used shape in measurements.
M L + M₁ 0 - m₂ L₂ = 0
M L - m₂ L₂ = 0
L₂ = L
From this answer we have several possibilities
* if the two masses are equal then L₂ = L
* If the masses are different, with M₂> M then L₂ = \frac{M}{M_{2}} L
Explanation:
Below is an attachment containing the solution.