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Artist 52 [7]
3 years ago
12

. Egbert is in a rowboat four miles from the nearest point on Egbert a straight shoreline. He wishes to reach a house 12 miles f

arther down the shore. If Egbert can row at a rate of 3 mi/hr and walk at a rate of 4 mi/hr, find the least amount of time required to reach the house. How far from the house should he land the rowboat? Justify your answer.
Physics
1 answer:
swat323 years ago
6 0

Answer:

t=\frac{13}{3} =4.33\ mi.hr^{-1}

Explanation:

Given:

  • Distance from the shore, s=4\ mi
  • distance of house from the shore, h=12\ mi
  • speed of rowing, v_r=3\ mi.hr^{-1}
  • speed of walking, v_w=4\ mi.hr^{-1}

<em>For the least amount of time to reach the house one must row at the nearest point on the shore and then walk from there.</em>

<u>Now the time taken to reach the shore:</u>

t_s=\frac{s}{v_s}

t_s=\frac{4}{3}\ mi.hr^{-1}

<u>Time taken in walking to house from the shore:</u>

t_h=\frac{h}{v_w}

t_h=\frac{12}{4}

t_h=\frac{12}{4}

t_h=3\ mi.hr^{-1}

<u>Therefore total time taken:</u>

t=t_h+t_s

t=\frac{13}{3} =4.33\ mi.hr^{-1}

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1000 kgm²/s, 1000 J

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Angular momentum of the system is given by

L=mvr+mvr\\\Rightarrow L=2mvr\\\Rightarrow L=2\times 100\times 2\times 2.5\\\Rightarrow L=1000\ kgm^2/s

The angular momentum of the system is 1000 kgm²/s

Rotational energy is given by

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Energy

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Displacement  = 4400m due west

Unknown:

Velocity = ?

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Velocity is defined as the displacement  per unit of time. It is expressed in m/s or km/hr:

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Velocity brainly.com/question/10883914

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vlabodo [156]

Answer:

The answer is below

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α = 75°

a) The direction of the wind is 75° in the south east direction while the airplane is heading 30° in the north east direction.

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