Answer:
It will have aim at a point "below" the insect.
From the insect's point of view, the fish will appear to be shallower than it actually is because a ray of light from the insect to the fish will be bent "towards" the normal when the ray enters the water
M = mass of the first sphere = 10 kg
m = mass of the second sphere = 8 kg
V = initial velocity of the first sphere before collision = 10 m/s
v = initial velocity of the second sphere before collision = 0 m/s
V' = final velocity of the first sphere after collision = ?
v' = final velocity of the second sphere after collision = 4 m/s
using conservation of momentum
M V + m v = M V' + m v'
(10) (10) + (8) (0) = (10) V' + (8) (4)
100 = (10) V' + 32
(10) V' = 68
V' = 6.8 m/s
Answer:
With the help of formula.
Explanation:
We can calculate the electric potential of any point through the formula of electric potential which is given below.
Electric potential = Coulomb constant x charge/ distance of separation.
Symbolically it can be written as, V = k q/ r where
V = electric potential
k = Coulomb constant
q = charge
r = distance of separation
If we have all these data, we can simply put the data in the formula and we will get the value of electric potential.
Answer:
Explanation:
Since the fly accumulated a positive charge of +73pC, it must have lost an equal number of negative charge of -73pC to the surface (because the housefly was neutral to begin with).
Therefore, to answer our question we have to ask ourselves <em>how many electrons combine to make -73pC of charge? </em>
The answer is since one electron carries a charge of 
, the number 
of electrons that make up -73pC 
are
Thus, the housefly lost about 456 million electrons to the surface!
