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Sliva [168]
2 years ago
6

The speed of light is 3 x 108 m/s (300,000,000 m/s). A light wave has a wavelength of 400 nm (0.0000004 m). What is the frequenc

y of the light
wave?
Physics
1 answer:
kirill115 [55]2 years ago
6 0

Explanation:

velocity = wavelength × frequency

3×10⁸ = 400/10⁹ × frequency

frequency = 3 × 10¹⁵ /400

frequency = 75×10¹¹Hz

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An "energy bar" contains 26 g of carbohydrates. For the steps and strategies involved in solving a similar problem, you may view
masha68 [24]

To solve this problem we will apply the definition of Power and Speed. In turn, we will consider that one gram of carbohydrate, according to numerous scientific studies, contributes around 17kJ of energy. Therefore, if this were true, the total energy of 26 grams would be

E = (26)(17000) = 4.42*10^5J

Power can be described as the amount of energy applied at a given time, that is,

P = \frac{E}{t} \rightarrow t = \frac{E}{P}

t = \frac{4.42*10^5}{380}

t = 1.16*10^3s

The speed is described as the distance traveled in a certain time, and its units in international system is m / s, converting and replacing we will have

v = 5km/h(\frac{1000m}{1km})(\frac{1h}{3600s})

v = 1.388m/s

Now,

v = \frac{d}{t} \rightarrow d = vt

The distance is,

d = vt

d = (1.388)(1.16*10^3)

d = 1610.08m

Therefore the distance walked is 1610.08m

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4 years ago
Una banda de rock toca en un nivel<br>de sonido de 80 dB ¿Cuál es la<br>intensidad de ese sonido?​
BabaBlast [244]
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3 years ago
.A coin rolls off the edge of a table. The coin
geniusboy [140]

Answer:

Apply the following formulae horizontally And get A value for time

Remember horizontal acceleration is zero

s  = ut +  \frac{1}{2}a {t}^{2}   \\ 0.8 = 1.7 \times t \\  \frac{0.8}{1.7}  = t \\ t = 0.47s

and then to find the height apply the same above equation vertically...remember vertical initial velocity is zero

s = ut +  \frac{1}{2} a {t}^{2}  \\ s =  \frac{1}{2}  \times 10 \times (0.47) ^{2}  \\ s = 1.1045m

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Answer:

21 m

Explanation:

The motion of the frog is a uniform motion (constant speed), therefore we can find the distance travelled by using

d=vt

where

d is the distance covered

v is the speed

t is the time

The frog in this problem has a speed of

v = 2.1 m/s

and therefore, after t = 10 s, the distance it covered is

d=(2.1)(10)=21 m

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4 years ago
In which year was the first Badminton game played in the Olympics
Kisachek [45]
Year 1972
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