Answer:
Moment of Inertia, I = 0.016 kgm²
Explanation:
Mass of the ball, m = 0.20 kg
Length of the pitcher's arm, l = 0.28
Radius of the circular arc, r = 0.28 m
Moment of Inertia is given by the formula:
I = mr²
I = 0.20 * 0.28²
I = 0.20 * 0.0784
I = 0.01568
I = 0.016 kgm²
Answer:
The resultant force would (still) be zero.
Explanation:
Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.
In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.
By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.
When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.
However, recall that before the 600-N force is removed, the friction on the crate is 400 N. The normal force on the crate (which is in the vertical direction) did not change. As a result, one can hence be assured that the maximum friction would be at least 400 N. That's sufficient for balancing the 200-N force to the right. Hence, the resultant force on the crate would still be zero, and the crate won't move.
Answer:
d. H + O2 ------ H2O
that's the formation of water
It means the speed of the object is increasing
and
there is a positive acceleration in the direction of the velocity
hence
there is a force acting on the object, in the direction of the velocity
Answer:
<em>The lighten travels 0.853 miles.</em>
Explanation:
Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.
v = 2x/t .......................................... Equation 1
making x the subject of the equation
x = vt/2........................................ Equation 2
Where v = velocity of sound in air, x = distance traveled by the sound, t = time
Given: v = 344 m/s t = 8 s
Substituting into equation 2
x = 344(8)/2
x = 1376 m.
x = 1376×0.00062 miles = 0.853 miles
<em>Thus the lighten travels 0.853 miles.</em>
