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VashaNatasha [74]
3 years ago
10

newton's second law state that a force on a drag racer is equal to the mass of the car times it's acceleration. one of the most

important factors determining the cars acceleration is the tires on the car. this is because the force accelerating the car forward is provided by
Physics
2 answers:
kaheart [24]3 years ago
7 0
I believe the answer you are looking for is the friction of the tires on the race track
sleet_krkn [62]3 years ago
7 0
The force being provided the car more specifically would be the torque of each individual tire multiplied by some friction coefficient between the tire and the concrete multiplied by 4 since there are 4 tires.
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A 10.0 cm object is 5.0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and th
fiasKO [112]
Let's use the mirror equation to solve the problem:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where f is the focal length of the mirror, d_o the distance of the object from the mirror, and d_i the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for d_i by using the numbers given in the text of the problem:
\frac{1}{12 cm}= \frac{1}{5 cm}+ \frac{1}{d_i}
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Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
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How long does it take to travel to Mercury while going 100,000 km per hour?
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It Would Take Aprroximately 1000 Years.
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a pumpkin with a mass of 2.5 kg was pushed toward a wall the average acceleration of the pumpkin was 10.7 miles per second squar
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If the magnetic flux through a loop increases according to the relation; where , is in milliweber (mWb) and t is in seconds. Cal
Alekssandra [29.7K]

The magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

<h3>emf induced in the loop</h3>

The magnitude of e.m.f induced in the loop is calculated as follows;

emf = dФ/dt

Ф = 6t² + 7t

dФ/dt = 12t + 7

at t = 2 seconds

emf = dФ/dt = 12(2) + 7 = 31 V

Thus,  the magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

Learn more about emf here: brainly.com/question/24158806

#SPJ1

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2 years ago
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