Answer:
The magnetic field 50m below the transmission line is 4 micro Tesla.
Explanation:
The magnetic field due to a current carrying wire at a distance is
where is the magnetic constant.
For the case of the power line we put in and to get:
.
Thus, the magnetic field 50m below the transmission line is 4 micro Tesla.
The correct answer is 1.07m.
The area surrounding an electric charge where its impact may be felt is known as the electric field. When another charge enters the field, the presence of an electric field may be felt. The electric field will either attract or repel the charge depending on its makeup. Any electric charge has a property known as the electric field. The charge and electrical force working in the field determine the strength or intensity of the electric field.
Here, is the charge per unit length, r is the distance from the wire, and
is the free space permittivity ε_0. Electric field due to the long straight wire is,
E= λ/2πε_0r
Rearrange the equation for r.
r=λ/2πε_0E
Substitute 2.41 N/C for E,
E=1.44×10^-10C/m
λ=8.85×10^-12C^2/Nm^2
r=(1.44×10^-10C/m)/(2(3.14)(8.85×10^-12C^2/Nm^2)(2.41N/C))
r=1.07m
At a distance of 1.07 m the magnitude of electric field is 2.41 N/C.
To learn more about electric field refer the link:
brainly.com/question/12821750
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Releasing any species into an environment it's not adapted to, or native to is dangerous because the species lacks the necessary adaptations to survive in the environment.
In the example of the frog, releasing it into a grassland would be a bad idea because the frog needs not only a "moist" area to thrive but it needs places to hide and plenty of insects to feed off of. Also, for reproduction it would need a pond, or some kind of water source!
I hope this is helpful!
A prominence is a loop of cool incandescent gas that extends above the photosphere. A solar flare is an explosive release of energy that comes from the sun and causes magnetic ditrubances.