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givi [52]
4 years ago
15

The half-life of plutonium-238 is 87.7 years. What percentage of the atoms in a sample of plutonium-238 will remain radioactive

after 263.1 years? % What percentage of the atoms in the same sample of plutonium-238 will have changed to another isotope after 263.1 years?
Physics
2 answers:
makkiz [27]4 years ago
8 0

The answer is 12.5 and then 87.5

TEA [102]4 years ago
5 0

(263.1 years) x (half-life / 87.7 years)  =  3 half-lifes

In 3 half-lifes, (1/2 x 1/2 x 1/2) = 1/8 of the atoms in a sample remain unchanged.

That's 12.5% that remain unchanged.

The other 87.5% of the atoms in the sample have decayed, and changed to either other isotopes of plutonium or into atoms of other elements.

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Q = 4.6E-6 C 
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<span>ε = 8.85E-12 F/m </span>
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4 years ago
To determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. it is found th
il63 [147K]

The difference in weight is due to the displacement of water (the buoyancy of water is acting on the athlete thus giving her smaller weight).<span>

The amount of weight displaced or the amount of buoyant force is: </span>

Fb = 690 N - 48 N

Fb = 642 N

From newtons law, F = m*g. Using this formula, we can calculate for the mass of water displaced:

m of water displaced = 642N / 9.8m/s^2

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Assuming a water density of 1 kg/L, and using the formula volume = mass/density:

V of water displaced = 65.5kg / 1kg/L = 65.5 L

The volume of water displaced is equal to the volume of athlete. Therefore:

V of athlete = 65.5 L

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m of athlete = 690 N/ 9.8m/s^2

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Knowing the volume and mass of athlete, her average density is therefore:

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5 0
3 years ago
Read 2 more answers
A hill is 132 m long and makes an angle of 12.0 degrees with the horizontal. As a 54 kg jogger runs up the hill, how much work d
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Answer:

14523.55J

Explanation:

The work done by the jogger against gravity is given by the following equation;

W=mgh.................(1)

where m is the mass, g is acceleration due to gravity taken as 9.8m/s^2 and h is the height of the hill.

Since the length of the hill is 132m and it is inclined at 12 degrees to the horizontal, the height is thus given as follows;

h=132sin12^o\\h=27.44m

Substituting this into equation (1) with all other necessary parameters, we obtain the following;

W=54*9.8*27.44\\W=14523.55J

4 0
3 years ago
No links plz!!
Pavlova-9 [17]

Answer:

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6 0
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