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Sladkaya [172]
3 years ago
11

Trace the path of a ray emitted from the tip of the object through the focal point of the mirror and then the reflected ray that

results. Start by extending the existing ray emitted from the tip of the object. Then create the reflected ray. Draw the vector for the reflected ray starting from the point where the incident focal ray hits the mirror. The location and orientation of the vector will be graded. The length of the vector will not be graded.

Physics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

1 / f = 1 / p + 1 / q

Explanation:

Mirror problems can be solved analytically with the constructor equation

         1 / f = 1 / p + 1 / q

An approximate solution can also be given using graphical methods, where two of three rays must be drawn,

1) A ray that passes through the focal length and bounces horizontally

2) A ray that passes through the center of curvature (c = 2f) of the mirror and does not deviate

3) A beam that comes horizontal and bounces through the focal

The attached shows the ray that passes through the focal length and bounces horizontally.

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Changes of state
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Answer:

Option A

Explanation:

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2 years ago
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A e B são dos blocos de massas 3,0 kg e 2,0 kg, respectivamente, que se movimentam juntos sobre uma superficie horizontal e perf
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F = m*a

30 N = (ma + mb) * a

30 = 5*a

a = 6 m/s ^2

F de B em A

30 - F de B,A = ma * a

30 - F de B em A = 3 * 6

30 - 18 = F de B em A

12 = F de B em A


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3 years ago
State Pascal's principle of transmission of pressure​
bulgar [2K]

Answer:

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4 years ago
Jenny and Alyssa are members of the cross-country team. On a training run, Jenny starts off and runs at a constant 3.8 m/s. Alys
guapka [62]

Answer:

285 seconds

Explanation:

Jenny speed is 3.8 m/s

Alyssa speed in 4.0 m/s

Alyssa starts after 15 seconds

Find the distance covered by Jenny, when Alyssa starts

Distance=Speed*time

Distance covered by Jenny in 15 seconds= 3.8×15=57m

Relative speed of the two members heading same direction will be;

4.0m/s-3.8m/s=0.2m/s

To find the time Alyssa catch up with Jenny you divide the distance to be covered by Alyssa by the relative speed of the two

Distance=57m, relative speed=0.2m/s  t=57/0.2 =285 seconds

=4.75 minutes

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3 years ago
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