Trace the path of a ray emitted from the tip of the object through the focal point of the mirror and then the reflected ray that
results. Start by extending the existing ray emitted from the tip of the object. Then create the reflected ray. Draw the vector for the reflected ray starting from the point where the incident focal ray hits the mirror. The location and orientation of the vector will be graded. The length of the vector will not be graded.
1 answer:
Answer:
1 / f = 1 / p + 1 / q
Explanation:
Mirror problems can be solved analytically with the constructor equation
1 / f = 1 / p + 1 / q
An approximate solution can also be given using graphical methods, where two of three rays must be drawn,
1) A ray that passes through the focal length and bounces horizontally
2) A ray that passes through the center of curvature (c = 2f) of the mirror and does not deviate
3) A beam that comes horizontal and bounces through the focal
The attached shows the ray that passes through the focal length and bounces horizontally.
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Answer:
1) It expresses the rate (top speed) at which it can move with time.
2) P = 20 W
3) h = 18 km
Explanation:
1) Power is the rate of transfer of energy.
⇒ Power =
i.e P =
Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.
2) m = 400g = 0.4 kg
t = 20 s
h = 100m
g = 10 m/
P =
=
=
P = 20 W
3) u = 600 m/s
g = 10 m/
From the third equation of free fall,
=
- 2gh
V is the final velocity, U is the initial velocity, h is the height.
0 = - 2 x 10 x h
0 = 360000 - 20h
20h = 360000
h =
= 18000
h = 18 km
The maximum height of the bullet would be 18 km.
Answer:
ΔF=125.22 %
Explanation:
We know that drag force on the car given as
=Drag coefficient
A=Projected area
v=Velocity
ρ=Density
All other quantity are constant so we can say that drag force and velocity can be given as
Now by putting the values
Percentage Change in the drag force
ΔF=125.22 %
Therefore force will increase by 125.22 %.
The correct answer is
B It increases.
In fact, the kinetic energy of a moving object is given by
where m is the mass of the object and v is its speed. We see that the kinetic energy is proportional to the mass and proportional to the square of the speed: in this problem, the speed of the object remains the same, while its mass increases, therefore the kinetic energy will increase as well.
B It increases.
In fact, the kinetic energy of a moving object is given by
where m is the mass of the object and v is its speed. We see that the kinetic energy is proportional to the mass and proportional to the square of the speed: in this problem, the speed of the object remains the same, while its mass increases, therefore the kinetic energy will increase as well.