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Nikolay [14]
3 years ago
11

What is the SI unit for speed?

Physics
2 answers:
alex41 [277]3 years ago
6 0
Meters per second should fit perfectly.

i wonder is this helping thou?
Maksim231197 [3]3 years ago
3 0
That is meters per second, same as velocity.
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A 30kg mass is brought from the earth to the moon what is the weight on the earth
ozzi

Answer:

Solution

verified

Verified by Toppr

Given:

Mass of body = 30 kg

gravitational acceleration on the moon = 1.62 m/s

2

Weight of the body on the moon = Mass of the body×gravitational acceleration on the moon=30×1.62=48 N

8 0
2 years ago
Since protons (p*) with a positive charge and neutrons (nº) without a charge are located in the
konstantin123 [22]

Answer:

A nucleus contains protons and neutrons . Protons are positively charged and neutrons are neutral . So charge of nucleus depends upon protons . Hence , neucleus is positively charged

Explanation:

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4 years ago
Which of the following is a form of potential energy? A chemical bond B a burning fire C a racing car D water boiling
Sveta_85 [38]
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You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
A force of 6n is exerted on a cart that is carrying a rock and produces an acceleration of 2 m/s2. if the cart has a mass of 1 k
Alex777 [14]
F=ma
m=f/a
m=6N/2 m per secon per second
m=3 kg.
If the cart is 1 kg then 3kg-1kg is 2kg.
The mass of the rock is 2kg.
4 0
4 years ago
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