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antoniya [11.8K]
2 years ago
5

Differences between weightlessness in space and weightlessness in earth​

Physics
2 answers:
zhuklara [117]2 years ago
6 0

Answer:

it depends on a person's own weight

ExtremeBDS [4]2 years ago
3 0

Answer:

The gravity is roughly the same. The inverse square law applies to gravity and that means that being 60 miles above Earth is about the same as being on Earth. The thing is, they are going really fast in an orbit and thus falling around the Earth. The weightlessness comes from a sort of cancellation of gravity pulling them down and their going perpendicular to that force. The forces are cancelling and making them relatively “weightless”. It’s not really weightlessness but just an equilibrium reached between the two accelerations of gravity and their motion against the pull of the Earth.

Explanation:

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Thomas records the masses of several rocks as 7.40 g, 7.85 g, 7.60 g, and 7.40 g. What is the mode of Thomas’s data set?
slamgirl [31]
Mode = 7.40 g

[ As it is repeating here ]

Hope this helps!
4 0
3 years ago
A roller coaster has a mass of 650 kg. It sits at the top of a hill with height 78 m. If it drops from this hill, how fast is it
Leto [7]

Answer:

The roller coaster is going at 39.1 m/s when it reaches the bottom

Explanation:

We use conservation of mechanical energy to solve this problem. So, we need to estimate the potential energy of the cart at the top of the hill while it is sitting steady there. Such will give us the cart initial Total Energy (TE) since its kinetic energy at that moment is zero (the cart is not moving, just sitting at the top of the hill).

Its initial potential energy (Ui) is therefore: Ui=m*g*h=650 * 9.8 * 78=496860 J

Notice also that all units given are in the SI system, (including the acceleration of gravity g) and therefore the answer is in Joules.

As we said, this initial potential energy equals the Total Energy  (TE) of the roller coaster because its initial Kinetic Energy (Ki) is zero.

When we look at what happens the instant the cart reaches the bottom, at that point it has all kinetic energy and zero potential energy (h is zero at the bottom of the hill). Final Kinetic Energy is by definition: Kf =\frac{1}{2} m*v^2=\frac{1}{2}650*v^2=325 v^2

Therefore, the conservation of mechanical energy tells us that:

ET_i=ET_F\\U_i+K_i=U_F+K_F\\496860 J +0J=0J+325v^2

We can solve for the final velocity of the roller coaster in this equation by solving for it in the equation:

496860 J +0J=0J+325v^2\\\\496860J=325v^2\\v^2=\frac{496860}{325} =1528.8\\v=\sqrt{1528.8} = 39.1 \frac{m}{s}

The velocity should result with units of meters/second since all quantities were given in SI units.

5 0
3 years ago
The momentum of blue whale with a mass of 146,000 kg and a top swimming speed of 24 km/hr is kg·m/s.
Kazeer [188]

The momentum of a blue whale with a mass of 146,000 kg and a top swimming speed of 24 km/hr is kg-m/s... the answer is:1,022,000 kg*m/s

3 0
3 years ago
If a wave were nine feet high, how much would the amplitude be?
Vinil7 [7]

'D. 18 feet' sounds right

3 0
3 years ago
Read 2 more answers
A sprinter starts from rest and reaches a speed of 15 m/s in 4.25 s. Find his acceleration
kakasveta [241]

Answer:

a=3.53 m/s^2

Explanation:

Vo=0 m/s (because he is not moving at the start)

V1=15 m/s

t= 4.25 s

a = (V1-Vo) / t = 15/4.25 = 3.53 m/s^2

5 0
3 years ago
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